A266313 Period 8 zigzag sequence; repeat [0, 1, 2, 3, 4, 3, 2, 1].
0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3, 4, 3, 2, 1, 0, 1, 2, 3, 4, 3
Offset: 0
Examples
G.f. = x + 2*x^2 + 3*x^3 + 4*x^4 + 3*x^5 + 2*x^6 + x^7 + x^9 + ... - _Michael Somos_, Feb 27 2020
Links
- Index entries for linear recurrences with constant coefficients, signature (1,0,0,-1,1).
Crossrefs
Programs
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Magma
&cat[[0, 1, 2, 3, 4, 3, 2, 1]: n in [0..10]];
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Maple
A266313:=n->[0, 1, 2, 3, 4, 3, 2, 1][(n mod 8)+1]: seq(A266313(n), n=0..100);
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Mathematica
CoefficientList[Series[x*(1 + x + x^2 + x^3)/(1 - x + x^4 - x^5), {x, 0, 100}], x]
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PARI
x='x+O('x^100); concat(0, Vec(x*(1+x+x^2+x^3)/(1-x+x^4-x^5))) \\ Altug Alkan, Dec 29 2015
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PARI
{a(n) = abs((n+4)\8*8-n)}; /* Michael Somos, Feb 27 2020 */
Formula
G.f.: x*(1+x+x^2+x^3)/(1-x+x^4-x^5).
a(n) = a(n-1) - a(n-4) + a(n-5) for n > 4.
a(n) = Sum_{i = 1..n} (-1)^floor((i-1)/4).
a(n) = abs(n - 8*round(n/8)). - Jon E. Schoenfield, Jan 01 2016
Euler transform of length 8 sequence [2, 0, 0, -2, 0, 0, 0, 1]. - Michael Somos, Feb 27 2020
a(n) = a(n-8) for n >= 8. - Wesley Ivan Hurt, Sep 07 2022
Comments