cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A266577 Square array read by descending antidiagonals: T(n,k) = ((2^(n+1) + 1)^(k-1) + 1)/2.

Original entry on oeis.org

1, 3, 1, 13, 5, 1, 63, 41, 9, 1, 313, 365, 145, 17, 1, 1563, 3281, 2457, 545, 33, 1, 7813, 29525, 41761, 17969, 2113, 65, 1, 39063, 265721, 709929, 592961, 137313, 8321, 129, 1, 195313, 2391485, 12068785, 19567697, 8925313, 1073345, 33025, 257, 1, 976563, 21523361, 205169337, 645733985, 580145313, 138461441, 8487297, 131585, 513, 1
Offset: 1

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Author

Ahmad J. Masad, Jan 01 2016

Keywords

Comments

The matrix M in the definition of A292625 is given by this sequence, also, for each natural number m and each natural number c, ((2^(m+1)+1)^c-1)*(the product of any (m+1) not necessarily distinct terms of the m-th row) is palindromic in base (2^(m+1)+1), see the MathOverflow link. - Ahmad J. Masad, Apr 19 2023
Conjecture: For integers n and m > 1, let b(n,m)=n^m+1, S(n,m) = set of numbers of the form (b(n,m)^k+...+b(n,m)^((n-1)*k)+1)/n, where k is any nonnegative integer. Then for each positive integer s, (b(n,m)^s-1)*(product of any m not necessarily distinct terms of S(n,m)) is palindromic in base b(n,m). - Ahmad J. Masad, Jan 11 2025
The conjecture is true. See my proof in MathOverflow (2025) link. - Max Alekseyev, May 15 2025

Examples

			The array begins:
  1   3  13  63 313
  1   5  41 365
  1   9 145
  1  17
  1
Example of the result concerning palindromic numbers:
Take m=2, c=4, 2^(m+1) + 1 = 2^3 + 1 = 9, we choose 3 not necessarily distinct terms from the second row. Let them be 41, 365, 365; then we get 41*365*365*(9^4 - 1) = 35832196000 = 112435534211_9, which is a palindromic number in base 9.
Example of the conjecture: assume n=5 and m=3, then b(5,3)=5^3+1=126. Assume k1=1 and k2=1 and k3=2 (they are three values since m=3). Assume s=3; then we have the calculation ((126+126^2+126^3+126^4+1)/5)^2*(126^2+126^4+126^6+126^8+1)/5*(126^3-1) which is equal to: 32807046133985032885720309126001 and this number has the base-126 expansion  (1,3,7,12,19,25,31,34,37,37,37,34,31,25,19,12,7,3,1)_126 which is a palindromic number in base 126.
		

Crossrefs

Cf. A034478.

Programs

  • Mathematica
    T[n_, k_] := ((2^(n + 1) + 1)^(k - 1) + 1)/2; Table[T[k, n - k + 1], {n, 1, 10}, {k, 1, n}] // Flatten (* Amiram Eldar, Sep 14 2022 *)
  • PARI
    tabl(n) = matrix(n, n, i, j, ((2^(i+1)+1)^(j-1)+1)/2); \\ Michel Marcus, Jan 02 2016

Extensions

a(31) corrected by Georg Fischer, Nov 07 2021