A268415 Balanced odious numbers: numbers with an odd number of runs of 1's in their binary expansion.
1, 2, 3, 4, 6, 7, 8, 12, 14, 15, 16, 21, 24, 28, 30, 31, 32, 37, 41, 42, 43, 45, 48, 53, 56, 60, 62, 63, 64, 69, 73, 74, 75, 77, 81, 82, 83, 84, 86, 87, 89, 90, 91, 93, 96, 101, 105, 106, 107, 109, 112, 117, 120, 124, 126, 127, 128, 133, 137, 138, 139, 141
Offset: 1
Examples
77 is a member because its binary expansion (1001101) has 3 runs of 1's, and 3 is odd.
Links
- Peter J. C. Moses (terms 1..1000) & Antti Karttunen, Table of n, a(n) for n = 1..8129
- Vladimir Shevelev, Two analogs of Thue-Morse sequence, arXiv:1603.04434 [math.NT], 2016.
Crossrefs
Programs
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Mathematica
balancedBinary:=Join[#,{0}]-Join[{0},#]&[IntegerDigits[#,2]]&; Flatten[Position[Map[Mod[Count[balancedBinary[#],1],2]&,Range[0,100]],1]-1] (* Peter J. C. Moses, Feb 04 2016 *) Select[Range[200],OddQ[Count[Split[IntegerDigits[#,2]],?(MemberQ[ #,1]&)]]&] (* _Harvey P. Dale, Mar 31 2019 *)
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Python
A268415_list = [i for i in range(10**6) if len(list(filter(bool,format(i,'b').split('0')))) % 2] # Chai Wah Wu, Mar 01 2016
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Scheme
(define A268415 (ZERO-POS 1 1 (COMPOSE -1+ A268411))) ;; requires also my IntSeq-library. - Antti Karttunen, Feb 05 2016
Formula
Other identities. For all n >= 1:
A268382(a(n)) = n.
Extensions
More terms from Peter J. C. Moses, Feb 04 2016
Comments