cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A270095 Numbers n for which A269233(n) is a record.

Original entry on oeis.org

0, 2, 6, 9, 12, 13, 22, 31, 32, 50, 73, 78, 123, 136, 147, 232, 248, 306, 323, 356, 396, 403, 435, 575, 684, 723, 802, 808, 909, 962, 1165, 1684, 1820, 2051, 2202, 2219, 2683, 2746, 3580, 4109, 4158, 4450, 4770
Offset: 1

Views

Author

Hans Havermann, Mar 10 2016

Keywords

Examples

			0 is in the list because A269233(0)=0 is initial.
2 is in the list because A269233(2)=3 is the first value greater than A269233(0)=0.
6 is in the list because A269233(6)=5 is the first value greater than A269233(2)=3.
9 is in the list because A269233(9)=8 is the first value greater than A269233(6)=5.
		

Crossrefs

A037053 Smallest prime containing exactly n 0's.

Original entry on oeis.org

2, 101, 1009, 10007, 100003, 1000003, 20000003, 100000007, 1000000007, 30000000001, 100000000003, 2000000000003, 40000000000001, 1000000000000037, 6000000000000001, 20000000000000003, 100000000000000003, 1000000000000000003, 60000000000000000007, 500000000000000000003
Offset: 0

Views

Author

Patrick De Geest, Jan 04 1999

Keywords

Comments

Certain entries require n+3 digits such as a(13). Those which do not require three digits besides n zeros are in A085824. Conjecture: a prime of this form, A037053, requires at most three judiciously placed nonzero digits, two on the exterior and one inside. - Robert G. Wilson v
The zeros in a(n) do not need to be consecutive. If the zeros must be consecutive we get a new sequence which agrees with this one up though a(31), but then here we have a(32) = 10000000000000000000000000000000603, whereas the smallest prime with exactly 32 consecutive zeros is 19000000000000000000000000000000009 = 19*10^33+9. - N. J. A. Sloane, Feb 20 2016
Sequence A269230 lists the indices (32, 43, 46, 49, 50, 60, 69, ...) for which a(n) does not have n consecutive digits '0', and gives more information about the smallest prime which has n consecutive digits '0': Sequence A269260 lists the values a > 9 such that the least prime with n *consecutive* '0's equals nextprime(a*10^(n+1)), for these indices n. - M. F. Hasler, Feb 20 2016 and Feb 22 2016
Since the definition requires "exactly" and not "at least" n 0's, the sequence is not increasing, e.g., a(22) = 10^24 + 49 > a(23) = 10^24 + 7. However, it seems that no term has more digits than its successor. - M. F. Hasler, Feb 20 2016
From Bob Selcoe, Feb 20 2016: (Start)
Conjecture 1: (following Robert G. Wilson v's conjecture above and insight provided by Hans Havermann): terms with two substrings of zeros have first digit of 1.
Conjecture 2: as n increases, there are more terms with two substrings of zeros than one consecutive string.
The logic is as follows: Let n = number of zeros and z = number of substrings of consecutive zeros contained in candidate primes. Candidates with two substrings of zeros (z=2) must be considered after only 72 smaller z=1 candidates have been considered and excluded, i.e., numbers of the form a[n zeros]b and 1[n zeros]ab, where a in {1..9}, b in {1,3,7,9}. After these 72 candidates are excluded, 36*n z=2 candidates are considered before having to consider only 36 additional z=1 candidates (i.e., 2[n zeros]ab), followed by 36*n additional z=2 candidates, etc. So as n increases, it becomes increasingly unlikely that any z=1 term appears. Additionally, the number of candidates increases as n increases for z>=3. For a given n, 1044 + 324*(n+1) candidates must be excluded before considering the smallest z=3: 1[n-2 zeros]10101. Since the probability p of n-digit primes occurring is p ~ 1/(n log 10) by the Prime Number Theorem, and the number of z in {1,2} candidates which must be excluded increases exponentially as n and z increase, it is unlikely that any z >= 3 term appears in A037053 and that first digit will be > 1 for any z=2 term.
Sequence A269233 lists the number of candidate primes < a(n); i.e., the number of excluded candidates.
(End)

Crossrefs

Cf. A037052, A034388, A085824. Least prime with n '1's,...,'9's: A037055, A037057, A037059, A037061, A037063, A037065, A037067, A037069, A037071. The indices of these primes are given in A037052 - A037070.
Cf. A269230, A269233 (number of candidate primes < a(n)), A269260.

Programs

  • Maple
    F:= proc(n)
    local a,b,cands,p;
    cands:= [seq(seq(10^(n+1)*a+b,b=[1,3,7,9]),a=1..9), seq(seq(seq(10^(n+2)+a*10^j+b,b=[1,3,7,9]),a=1..9),j=1..n+1)];
    for p in cands do if isprime(p) then return p fi od;
    error("No candidate is prime");
    end proc:
    2, seq(F(n),n=1..40); # Robert Israel, Feb 19 2016
  • Mathematica
    f[n_] := Block[{pc}, a = 1; While[a < 10, b = 1; While[b < 10, pc = a*10^(n + 1) + b; If[PrimeQ[pc], Goto[fini]]; b += 2]; a++]; e = 1; While[e < n + 2, b = 1; While[b < 10, c = 1; While[c < 10, pc = 10^(n + 2) + b*10^e + c; If[ PrimeQ[pc], Goto[ fini]]; c += 2]; b++]; e++]; Label[ fini]; pc]; f[0] = 2; Array[f, 25, 0] (* Robert G. Wilson v, Feb 21 2016 *)
  • PARI
    A037053(n)={n&&forstep(i=n=10^(n+1),9*n,n,nextprime(i)p*=10, forstep(j=i+p,i+9*p,p,nextprime(j)M. F. Hasler, Feb 19 2016

Formula

a(n) = prime(A037052(n)). - Amiram Eldar, Jul 21 2025

Extensions

More terms from Victoria A Sapko (vsapko(AT)canes.gsw.edu), Aug 16 2002
Edited by Robert G. Wilson v, Jul 04 2003
Sequence rechecked (by request) and edited by Charles R Greathouse IV, Aug 03 2010
Extended with a(0) = 2 and three lines of data completed by M. F. Hasler, Feb 19 2016
Showing 1-2 of 2 results.