A271914 Symmetric array read by antidiagonals: T(n,k) (n>=1, k>=1) = maximal number of points that can be chosen in an n X k rectangular grid such that no three distinct points form an isosceles triangle.
1, 2, 2, 3, 2, 3, 4, 4, 4, 4, 5, 4, 4, 4, 5, 6, 5, 5, 5, 5, 6, 7, 6, 6, 6, 6, 6, 7, 8, 7, 8, 7, 7, 8, 7, 8, 9, 8, 8, 8, 8, 8, 8, 8, 9, 10, 9, 10, 9, 9, 9, 9, 10, 9, 10
Offset: 1
Examples
The array begins: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, ... 2, 2, 4, 4, 5, 6, 7, 8, 9, 10, ... 3, 4, 4, 5, 6, 8, 8, 10, 10, 12, ... 4, 4, 5, 6, 7, 8, 9, 10, 11, 12, ... 5, 5, 6, 7, 8, 9, 10, 12, 12, 14, ... 6, 6, 8, 8, 9, 10, 11, 12, 12, 14, ... 7, 7, 8, 9, 10, 11, 12, 13, 14, 16, ... 8, 8, 10, 10, 12, 12, 13, 14, 16, 16, ... 9, 9, 10, 11, 12, 12, 14, 16, 16, 18, ... 10, 10, 12, 12, 14, 14, 16, 16, 18, 18, ... ... As a triangle: 1, 2, 2, 3, 2, 3, 4, 4, 4, 4, 5, 4, 4, 4, 5, 6, 5, 5, 5, 5, 6, 7, 6, 6, 6, 6, 6, 7, 8, 7, 8, 7, 7, 8, 7, 8, 9, 8, 8, 8, 8, 8, 8, 8, 9, 10, 9, 10, 9, 9, 9, 9, 10, 9, 10, ... Illustration for T(2,3) = 4: XOX XOX Illustration for T(2,5) = 5: XXXXX OOOOO Illustration for T(3,5) = 6 (this left edge + top edge construction - or a slight modification of it - works in many cases): OXXXX XOOOO XOOOO Illustration for T(3,6) = 8: XXOOXX OOOOOO XXOOXX Illustration for T(3,8) = 10: OXXXXXXO XOOOOOOX XOOOOOOX Illustration for T(6,9) = 12: OXOOOOOOX OOXXXXXXO OOOOOOOOO OXOOOOOOX OXOOOOOOX OOOOOOOOO From _Bob Selcoe_, Apr 24 2016 (Start) Two symmetric illustrations for T(6,9) = 12: Grid 1: X X O O O O O X X O O O O O O O O O O O O O O O O O O O X X X O X X X O X O O O O O O O X O O O O O O O O O Grid 2: X O O O O O O O X X O O O O O O O X O O O O O O O O O O X X X O X X X O X O O O O O O O X O O O O O O O O O (Note that a symmetric solution is obtained for T(5,9) = 12 by removing row 6) (End)
Links
- Rob Pratt, Complete list of examples where T(n,k) != n+k-2 for 10 >= n >= k >= 2. Note T(9,6) = T(6,9) = 12, which is n+k-3.
Formula
From Chai Wah Wu, Nov 30 2016: (Start)
T(n,k) >= max(n,k).
T(n,max(k,m)) <= T(n,k+m) <= T(n,k) + T(n,m).
T(n,1) = n.
T(n,2) = n for n > 3.
For n > 4, T(n,3) >= n+1 if n is odd and T(n,3) >= n+2 if n is even.
Conjecture: For n > 4, T(n,3) = n+1 if n is odd and T(n,3) = n+2 if n is even.
Conjecture: If n is even, then T(n,k) <= n+k-2 for k >= 2n.
(End)
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