A279913 Largest n-digit number ending in n.
1, 92, 993, 9994, 99995, 999996, 9999997, 99999998, 999999999, 9999999910, 99999999911, 999999999912, 9999999999913, 99999999999914, 999999999999915, 9999999999999916, 99999999999999917, 999999999999999918, 9999999999999999919, 99999999999999999920
Offset: 1
Programs
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Mathematica
Table[n + 10^n - 10^(1 + Floor[Log10[n]]), {n, 100}] (* Wesley Ivan Hurt, Mar 30 2020 *) -
PARI
a(n) = 10^n + n - 10^(#Str(n)); \\ Michel Marcus, Jul 25 2022
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Python
def A279913(n): return 10**n+n-10**(len(str(n))) # Chai Wah Wu, Jul 25 2022
Formula
a(n) = n + 10^n - 10^(1 + floor(log_10(n))). - Wesley Ivan Hurt, Mar 30 2020
a(n) = 10^n - A089186(n). - Michel Marcus, Jul 25 2022