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A287272 a(n) is the number of zeros of the Laguerre L(n, x) polynomial in the open interval (-1, +1).

Original entry on oeis.org

0, 0, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5
Offset: 0

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Author

Michel Lagneau, May 22 2017

Keywords

Comments

The Laguerre polynomials are given by the sum: L(n,x) = Sum_{k=0..n} ((-1)^k)/k!*binomial(n,k)*x^k.
The first few Laguerre polynomials are:
L(0,x) = 1,
L(1,x) = -x + 1,
L(2,x) = ( x^2 - 4*x + 2)/2,
L(3,x) = (-x^3 + 9*x^2 - 18*x + 6)/6,
L(4,x) = ( x^4 - 16*x^3 + 72*x^2 - 96*x + 24)/24,
L(5,x) = (-x^5 + 25*x^4 - 200*x^3 + 600*x^2 - 600*x + 120)/120.
The number of occurrences a(n) = 0, 1, 2,.. is given by the sequence {2, 6, 11, 16, 21, ...}.

Examples

			a(3) = 1 because the zeros of L(3,x) = (-x^3 + 9*x^2 - 18*x + 6)/6 are x1=.4157745568..., x2=2.294280360... and x3=6.289945083... with the root x1 in the open interval (-1, +1). Hence, a(3) = 1.
		

Crossrefs

Cf. A066667.

Programs

  • Maple
    for n from 0 to 90 do:it:=0:
    y:=[fsolve(expand(LaguerreL(n,x)),x,real)]:for m from 1 to nops(y) do:if abs(y[m])<1 then it:=it+1:else fi:od: printf(`%d, `, it):od: