A289780 p-INVERT of the positive integers (A000027), where p(S) = 1 - S - S^2.

1, 4, 14, 47, 156, 517, 1714, 5684, 18851, 62520, 207349, 687676, 2280686, 7563923, 25085844, 83197513, 275925586, 915110636, 3034975799, 10065534960, 33382471801, 110713382644, 367182309614, 1217764693607, 4038731742156, 13394504020957, 44423039068114

Offset: 0

Author

Clark Kimberling, Aug 10 2017

Keywords

• nonn
• easy

Comments

Suppose s = (c(0), c(1), c(2), ...) is a sequence and p(S) is a polynomial. Let S(x) = c(0)*x + c(1)*x^2 + c(2)*x^3 + ... and T(x) = (-p(0) + 1/p(S(x)))/x. The p-INVERT of s is the sequence t(s) of coefficients in the Maclaurin series for T(x).

Taking p(S) = 1 - S gives the INVERT transform of s, so that p-INVERT is a generalization of the INVERT transform (e.g., A033453).

Guide to p-INVERT sequences using p(S) = 1 - S - S^2:

t(A000012) = t(1,1,1,1,1,1,1,...) = A001906

t(A000290) = t(1,4,9,16,25,36,...) = A289779

t(A000027) = t(1,2,3,4,5,6,7,8,...) = A289780

t(A000045) = t(1,2,3,5,8,13,21,...) = A289781

t(A000032) = t(2,1,3,4,7,11,14,...) = A289782

t(A000244) = t(1,3,9,27,81,243,...) = A289783

t(A000302) = t(1,4,16,64,256,...) = A289784

t(A000351) = t(1,5,25,125,625,...) = A289785

t(A005408) = t(1,3,5,7,9,11,13,...) = A289786

t(A005843) = t(2,4,6,8,10,12,14,...) = A289787

t(A016777) = t(1,4,7,10,13,16,...) = A289789

t(A016789) = t(2,5,8,11,14,17,...) = A289790

t(A008585) = t(3,6,9,12,15,18,...) = A289795

t(A000217) = t(1,3,6,10,15,21,...) = A289797

t(A000225) = t(1,3,7,15,31,63,...) = A289798

t(A000578) = t(1,8,27,64,625,...) = A289799

t(A000984) = t(1,2,6,20,70,252,...) = A289800

t(A000292) = t(1,4,10,20,35,56,...) = A289801

t(A002620) = t(1,2,4,6,9,12,16,...) = A289802

t(A001906) = t(1,3,8,21,55,144,...) = A289803

t(A001519) = t(1,1,2,5,13,34,...) = A289804

t(A103889) = t(2,1,4,3,6,5,8,7,,...) = A289805

t(A008619) = t(1,1,2,2,3,3,4,4,...) = A289806

t(A080513) = t(1,2,2,3,3,4,4,5,...) = A289807

t(A133622) = t(1,2,1,3,1,4,1,5,...) = A289809

t(A000108) = t(1,1,2,5,14,42,...) = A081696

t(A081696) = t(1,1,3,9,29,97,...) = A289810

t(A027656) = t(1,0,2,0,3,0,4,0,5...) = A289843

t(A175676) = t(1,0,0,2,0,0,3,0,...) = A289844

t(A079977) = t(1,0,1,0,2,0,3,...) = A289845

t(A059841) = t(1,0,1,0,1,0,1,...) = A289846

t(A000040) = t(2,3,5,7,11,13,...) = A289847

t(A008578) = t(1,2,3,5,7,11,13,...) = A289828

t(A000142) = t(1!, 2!, 3!, 4!, ...) = A289924

t(A000201) = t(1,3,4,6,8,9,11,...) = A289925

t(A001950) = t(2,5,7,10,13,15,...) = A289926

t(A014217) = t(1,2,4,6,11,17,29,...) = A289927

t(A000045*) = t(0,1,1,2,3,5,...) = A289975 (* indicates prepended 0's)

t(A000045*) = t(0,0,1,1,2,3,5,...) = A289976

t(A000045*) = t(0,0,0,1,1,2,3,5,...) = A289977

t(A290990*) = t(0,1,2,3,4,5,...) = A290990

t(A290990*) = t(0,0,1,2,3,4,5,...) = A290991

t(A290990*) = t(0,0,01,2,3,4,5,...) = A290992

Examples

			Example 1:  s = (1,2,3,4,5,6,...) = A000027 and p(S) = 1 - S.
S(x) = x + 2x^2 + 3x^3 + 4x^4 + ...
p(S(x)) = 1 - (x + 2x^2 + 3x^3 + 4x^4 + ... )
- p(0) + 1/p(S(x)) = -1 + 1 + x + 3x^2 + 8x^3 + 21x^4 + ...
T(x) = 1 + 3x + 8x^2 + 21x^3 + ...
t(s) = (1,3,8,21,...) = A001906.
***
Example 2:  s = (1,2,3,4,5,6,...) = A000027 and p(S) = 1 - S - S^2.
S(x) =  x + 2x^2 + 3x^3 + 4x^4 + ...
p(S(x)) = 1 - ( x + 2x^2 + 3x^3 + 4x^4 + ...) - ( x + 2x^2 + 3x^3 + 4x^4 + ...)^2
- p(0) + 1/p(S(x)) = -1 + 1 + x + 4x^2 + 14x^3 + 47x^4 + ...
T(x) = 1 + 4x + 14x^2 + 47x^3 + ...
t(s) = (1,4,14,47,...) = A289780.
		

Links

• Clark Kimberling, Table of n, a(n) for n = 0..1000
• Index entries for linear recurrences with constant coefficients, signature (5, -7, 5, -1)

Crossrefs

Cf. A000027.

Programs

GAP

P:=[1,4,14,47];; for n in [5..10^2] do P[n]:=5*P[n-1]-7*P[n-2]+5*P[n-3]-P[n-4]; od; P; # Muniru A Asiru, Sep 03 2017

Mathematica

z = 60; s = x/(1 - x)^2; p = 1 - s - s^2;
Drop[CoefficientList[Series[s, {x, 0, z}], x], 1] (* A000027 *)
Drop[CoefficientList[Series[1/p, {x, 0, z}], x], 1] (* A289780 *)

PARI

x='x+O('x^99); Vec((1-x+x^2)/(1-5*x+7*x^2-5*x^3+x^4)) \\ Altug Alkan, Aug 13 2017

Formula

G.f.: (1 - x + x^2)/(1 - 5 x + 7 x^2 - 5 x^3 + x^4).

a(n) = 5*a(n-1) - 7*a(n-2) + 5*a(n-3) - a(n-4).