A290843 Numbers k such that the sum of digits of k^3 is 4^3 = 64.

1192, 1366, 1426, 1435, 1753, 1786, 1813, 1816, 1912, 1942, 1999, 2116, 2389, 2395, 2398, 2413, 2566, 2599, 2632, 2635, 2653, 2692, 2713, 2872, 2899, 2992, 3022, 3031, 3103, 3199, 3289, 3295, 3298, 3301, 3355, 3361, 3382, 3394, 3409, 3415, 3442, 3466, 3475

Offset: 1

Author

Seiichi Manyama, Aug 12 2017

Keywords

• nonn
• base

Examples

			1192^3 = 1693669888, 1 + 6 + 9 + 3 + 6 + 6 + 9 + 8 + 8 + 8 = 64 = 4^3.
11*(10^(n+2) + 1) is a term for all n > 0. - _Altug Alkan_, Aug 12 2017
		

Links

• Seiichi Manyama, Table of n, a(n) for n = 1..10000

Crossrefs

Numbers k such that sum of digits of k^3 is m^3: A107679 (m=2), A290842 (m=3), this sequence (m=4), A159462 (m=5), A159463 (m=6).

Cf. A067075.

Programs

Mathematica

Select[Range[3500],Total[IntegerDigits[#^3]]==64&] (* Harvey P. Dale, Aug 04 2019 *)

PARI

isok(n) = sumdigits(n^3) == 64; \\ Altug Alkan, Aug 12 2017