A302752 Numbers k such that k divides the sum of largest parts of all partitions of k.
1, 3, 4, 5, 11, 197, 487, 928, 10995, 19318
Offset: 1
Examples
5 is in the sequence because we have [5], [4, 1], [3, 2], [3, 1, 1], [2, 2, 1], [2, 1, 1, 1], [1, 1, 1, 1, 1] and 5 + 4 + 3 + 3 + 2 + 2 + 1 = 20 is divisible by 5.
Programs
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Mathematica
Select[Range[200],Mod[Total[IntegerPartitions[#][[;;,1]]],#]==0&] (* The program generates the first six terms of the sequence. *) (* Harvey P. Dale, Oct 03 2023 *)
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