A307698 Number of evolutionary duplication-loss-histories with n leaves of the caterpillar species tree with 4 leaves.
4, 39, 495, 7235, 115303, 1948791, 34379505, 626684162, 11722058693, 223870302588, 4349161774626, 85701267415112, 1709101664822416, 34432888701965454, 699810795294490974, 14331183304458656628, 295434131968070459359, 6125911207605272841753, 127680054133385458855845
Offset: 1
Keywords
Examples
The caterpillar species tree with 4 leaves is equal to a / \ b 4 / \ c 3 / \ 1 2 For convenience the internal nodes are labeled by a,b,c, and the leaves by 1,2,3,4. The associated nodes in the histories will be denoted by the same labels. The a(1)=4 histories with n=1 leaf are created by the following growth process: a a a a / / / \ b b b 4 / / \ c c 3 / \ 1 2 after three loss events each.
Links
- C. Chauve, Y. Ponty, M. Wallner, Counting and sampling gene family evolutionary histories in the duplication-loss and duplication-loss-transfer models, arXiv preprint arXiv:1905.04971 [math-CO], 2019.
Crossrefs
Programs
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PARI
my(z = 'z + O('z^25), t = sqrt(1-4*z), u = sqrt(-5+6*t+4*z), v = sqrt(-t*u+3*t+3*u-4)); Vec(1/2-(1/2)*sqrt(-4-t*v+3*t+3*v)) \\ Michel Marcus, May 07 2019
Formula
G.f.: 1/2 - (1/2)*sqrt(-4 - t*v + 3*t + 3*v) where t = sqrt(1 - 4*z), u = sqrt(-5 + 6*t + 4*z) and v = sqrt(-t*u + 3*t + 3*u - 4).
Comments