A316098 Abundant numbers that differ from the next abundant number by 4.
20, 36, 56, 66, 80, 84, 96, 104, 108, 140, 156, 176, 192, 200, 204, 216, 224, 260, 272, 276, 300, 308, 320, 336, 360, 368, 380, 392, 396, 416, 440, 444, 456, 464, 476, 486, 500, 516, 528, 540, 546, 560, 572, 576, 608, 612, 620, 636, 644, 650, 680, 696, 704
Offset: 1
Keywords
Examples
20 is abundant, 21, 22 and 23 are deficient, 24 is abundant. 36 is abundant, 37, 38 and 39 are deficient, 40 is abundant.
Links
- Muniru A Asiru, Table of n, a(n) for n = 1..10000
Crossrefs
Programs
-
GAP
A:=Filtered([1..800],n->Sigma(n)>2*n);; a:=List(Filtered([1..Length(A)-1],i->A[i+1]-A[i]=4),j->A[j]);
-
Maple
with(numtheory): A:=select(n->sigma(n)>2*n,[$1..800]): a:=seq(A[i],i in select(n->A[n+1]-A[n]=4,[$1..nops(A)-1]));
-
Mathematica
q[n_] := DivisorSigma[1,n] > 2 n; Select[Range[704], q[#] && q[# + 4] && ! q[# + 1] && ! q[# + 2] && ! q[# + 3] &] (* Giovanni Resta, Jul 01 2018 *) SequencePosition[Table[If[DivisorSigma[1,n]>2n,1,0],{n,750}],{1,0,0,0,1}][[;;,1]] (* Harvey P. Dale, Mar 02 2023 *)
-
PARI
list(lim) = {my(k = 1, k2); for(k2 = 2, lim, if(sigma(k2, -1) > 2, if(k2 == k1 + 4, print1(k1, ", ")); k1 = k2));} \\ Amiram Eldar, Mar 01 2025