A316791 a(n) is the least prime p such that the second forward difference of three consecutive primes p, q and r is n = (p - 2q + r)/2.
3, 5, 29, 503, 137, 109, 1063, 1931, 521, 7951, 1949, 1667, 5743, 2969, 1321, 15817, 9547, 28349, 45433, 20807, 15679, 113837, 43793, 19603, 40283, 25469, 40637, 156151, 79697, 34057, 282487, 134507, 552401, 770663, 31393, 188021, 480203, 461707, 281429, 1078241, 265619, 637937
Offset: 0
Keywords
Examples
a(0) = 3 since the three consecutive primes {3, 5, 7} have an sfd of 0; a(1) = 5 since the three consecutive primes {5, 7, 11} have an sfd of 2; a(2) = 29 since the three consecutive primes {29, 31, 37} have an sfd of 4; a(3) = 503 since the three consecutive primes {503, 509, 521} have an sfd of 6; a(4) = 137 since the three consecutive primes {137, 139, 149} have an sfd of 8; etc.
Links
- Eric Weisstein's World of Mathematics, Forward Difference.
Programs
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Mathematica
p = 2; q = 3; r = 5; t[_] := 0; While[p < 1100000, d = p - 2q + r; If[ t[d] == 0, t[d] = p]; p = q; q = r; r = NextPrime@ r]; Array[ t[2#] &, 42, 0]
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PARI
a(n) = my(p=2, q=3); while ((p - 2*q + nextprime(q+1))/2 != n, p=q; q=nextprime(q+1)); p; \\ Michel Marcus, Mar 08 2023
Comments