A316792 a(n) is the least prime p such that the second forward difference of three consecutive primes p, q and r is n = -(p - 2q + r)/2.
3, 7, 23, 1531, 139, 113, 523, 1069, 887, 6397, 1129, 3137, 5351, 2971, 1327, 14107, 9973, 19333, 84871, 16141, 15683, 73189, 31907, 28229, 35617, 35677, 44293, 43331, 107377, 34061, 221327, 134513, 31397, 480209, 173359, 332317, 933073, 736279, 265621, 843911, 404851, 155921
Offset: 0
Keywords
Examples
a(0) = 3 since the three consecutive primes {3, 5, 7} have an sfd of 0; a(1) = 7 since the three consecutive primes {7, 11, 13} have a sfd of -2; a(2) = 23 since the three consecutive primes {23, 29, 31} have a sfd of -4; a(3) = 1531 since the three consecutive primes {1531, 1543, 1549} have an sfd of -6; a(4) = since the three consecutive primes {} have an sfd of -8; etc.
Links
- Eric Weisstein's World of Mathematics, Forward Difference.
Programs
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Mathematica
p = 2; q = 3; r = 5; t[_] := 0; While[p < 1000000, d = p - 2q + r; If[ t[d] == 0, t[d] = p]; p = q; q = r; r = NextPrime@ r]; Array[ t[-2#] &, 42, 0]
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PARI
a(n) = my(p=2, q=3); while ((p - 2*q + nextprime(q+1))/2 != -n, p=q; q=nextprime(q+1)); p; \\ Michel Marcus, Mar 08 2023
Comments