cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A318970 a(1) = 3; for n > 1, a(n) = 2^(a(n-1) - 1) + 5.

Original entry on oeis.org

3, 9, 261, 1852673427797059126777135760139006525652319754650249024631321344126610074238981
Offset: 1

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Author

Max Alekseyev, Sep 06 2018

Keywords

Comments

a(n) divides a(n+1) for n <= 4, but it is unknown if this divisibility holds for larger n. In other words, it is unknown if this sequence is a subsequence of A245594.
Modulo any m > 1, the sequence stabilizes within the first A227944(m) <= log_2(m) terms. That is, for any n >= A227944(m), we have a(n) == a(A227944(m)) == A318989(m) (mod m).
It follows that the prime divisors of the terms (cf. A318971) are very sparse: if prime p does not divide any of the first log_2(p) terms, then p does not divide any term.

Crossrefs

Programs

  • Magma
    [n le 1 select 3 else 2^(Self(n-1)-1)+5: n in [1..4]]; // Vincenzo Librandi, Sep 07 2018
  • Mathematica
    RecurrenceTable[{a[1]==3, a[n]==2^(a[n-1] - 1) + 5}, a, {n, 4}] (* Vincenzo Librandi, Sep 07 2018 *)

A318989 Limiting value of A318970(k) mod n as k grows.

Original entry on oeis.org

0, 1, 0, 1, 1, 3, 2, 5, 0, 1, 6, 9, 1, 9, 6, 5, 4, 9, 14, 1, 9, 17, 14, 21, 6, 1, 18, 9, 0, 21, 6, 5, 6, 21, 16, 9, 2, 33, 27, 21, 6, 9, 3, 17, 36, 37, 19, 21, 16, 31, 21, 1, 6, 45, 6, 37, 33, 29, 34, 21, 52, 37, 9, 5, 1, 39, 40, 21, 60, 51, 42, 45, 42, 39, 6, 33, 72, 27, 28, 21, 72, 47, 56, 9, 21, 3, 0, 61, 37, 81, 79, 37, 6, 19, 71, 69, 11, 65, 72, 81
Offset: 1

Views

Author

Max Alekseyev, Sep 06 2018

Keywords

Comments

Is there a prime p in A318971 such that a(p) is nonzero?

Crossrefs

Formula

a(n) = A318970(k) mod n holds for any k >= A227944(n). In particular, a(n) = A318970(A227944(n)) mod n.
Showing 1-2 of 2 results.