cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A319854 Number of ways to write n as the sum of 4 positive integers a, b, c, d such that d < b and a/b - c/d = (a - c)/(b + d).

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 2, 0, 1, 1, 3, 1, 1, 1, 3, 3, 2, 1, 3, 2, 4, 2, 2, 3, 6, 3, 4, 2, 5, 3, 7, 4, 3, 4, 6, 5, 9, 2, 7, 4, 6, 5, 9, 5, 6, 6, 8, 3, 9, 7, 12, 7, 6, 6, 11, 5, 12, 6, 11, 7, 12, 6, 9, 10, 12, 7, 16, 5, 13, 8, 14, 9, 11, 9, 15, 11, 14
Offset: 1

Views

Author

Hugo Pfoertner and Rainer Rosenthal, Sep 29 2018

Keywords

Comments

Number of ways to write n as the sum of 4 positive integers a, b, c, d such that d < b and a*d^2 = b^2*c. - Robert Israel, Oct 04 2018

Examples

			a(8) = 1: 4/2 - 1/1 = (4 - 1)/(2 + 1) = 1;
a(11) = 1: 4/4 - 1/2 = (4 - 1)/(4 + 2) = 1/2;
a(13) = 1: 8/2 - 2/1 = (8 - 2)/(2 + 1) = 2;
a(14) = 2: 4/6 - 1/3 = (4 - 1)/(6 + 3) = 1/3, 9/3 - 1/1 = (9 - 1)/(3 + 1) = 2;
a(16) = 1: 8/4 - 2/2 = (8 - 2)/(4 + 2) = 1;
a(17) = 1: 4/8 - 1/4 = (4 - 1)/(8 + 4) = 1/4;
a(18) = 3: 9/3 - 4/2 = (9 - 4)/(3 + 2) = 1, 9/6 - 1/2 = (9 - 1)/(6 + 2) = 1, 12/2 - 3/1 = (12 - 3)/(2 + 1) = 3.
		

Crossrefs

Programs

  • Maple
    N:= 1000: # for a(1)..a(N)
    V:= Vector(N):
    for d from 1 to N/2 do
      for b from d+1 to N-d do
        u:= d^2/igcd(b,d)^2;
        for c from u by u  do
          v:= c*b^2/d^2+b+c+d;
          if v > N then break fi;
          V[v]:= V[v]+1
    od od od:
    convert(V,list); # Robert Israel, Oct 04 2018
  • Mathematica
    M = 100; Clear[V]; V[_] = 0;
    For[d = 1, d <= M/2, d++,
      For[b = d+1, b <= M-d, b++,
        u = d^2/GCD[b, d]^2;
        For[c = u, True, c = c+u,
          v = c*b^2/d^2 + b + c + d;
          If[v > M, Break[]];
          V[v] = V[v]+1
    ]]];
    Array[V, M] (* Jean-François Alcover, Apr 02 2019, after Robert Israel *)
  • PARI
    m=84;v=vector(m);for(a=1,m,for(b=1,m,for(c=1,m,for(d=1,b-1,n=a+b+c+d;if(n<=m,if((a/b-c/d)==((a-c)/(b+d)),v[n]++))))));v