A320510 Number of partitions of n such that the successive differences of consecutive parts are decreasing, and first difference < first part.

1, 1, 2, 1, 2, 2, 2, 2, 4, 2, 3, 4, 3, 4, 6, 3, 5, 6, 5, 6, 9, 5, 7, 9, 8, 8, 11, 8, 11, 13, 10, 12, 15, 11, 15, 16, 14, 16, 21, 15, 20, 22, 18, 21, 26, 21, 24, 28, 25, 28, 33, 26, 32, 34, 33, 36, 40, 34, 40, 45, 40, 43, 49, 43, 52, 54, 49, 54, 62, 56, 62, 64, 61, 67, 75, 66

Offset: 0

Author

Seiichi Manyama, Oct 14 2018

Keywords

• nonn

Comments

Partitions are usually written with parts in descending order, but the conditions are easier to check visually if written in ascending order.

The differences of a sequence are defined as if the sequence were increasing, so for example the differences of (6,3,1) (with the last part taken to be 0) are (-3,-2,-1). Then a(n) is the number of integer partitions of n whose differences (with the last part taken to be 0) are strictly decreasing. The Heinz numbers of these partitions are given by A325461. Of course, the number of such integer partitions of n is also the number of reversed integer partitions of n whose differences are strictly decreasing, which is the author's interpretation. - Gus Wiseman, May 04 2019

Examples

			There are a(29) = 13 such partitions of 29:
01: [29]
02: [10, 19]
03: [11, 18]
04: [12, 17]
05: [13, 16]
06: [14, 15]
07: [6, 10, 13]
08: [6, 11, 12]
09: [7, 10, 12]
10: [7, 11, 11]
11: [8, 10, 11]
12: [9, 10, 10]
13: [4, 7, 9, 9]
There are a(30) = 10 such partitions of 30:
01: [30]
02: [11, 19]
03: [12, 18]
04: [13, 17]
05: [14, 16]
06: [15, 15]
07: [6, 11, 13]
08: [7, 11, 12]
09: [8, 11, 11]
10: [4, 7, 9, 10]
		

Links

• Fausto A. C. Cariboni, Table of n, a(n) for n = 0..2000 (terms 0..300 from Seiichi Manyama)
• Gus Wiseman, Sequences counting and ranking integer partitions by the differences of their successive parts.

Crossrefs

Cf. A240026, A240027, A320466, A320470, A320509.

Cf. A320385 (distinct parts, decreasing, and first difference < first part).

Cf. A007294, A007862, A325324, A325358, A325393, A325461.

Programs

Mathematica

Table[Length[Select[IntegerPartitions[n],Greater@@Differences[Append[#,0]]&]],{n,0,30}] (* Gus Wiseman, May 04 2019 *)

Ruby

def partition(n, min, max)
  return [[]] if n == 0
  [max, n].min.downto(min).flat_map{|i| partition(n - i, min, i).map{|rest| [i, *rest]}}
end
def f(n)
  return 1 if n == 0
  cnt = 0
  partition(n, 1, n).each{|ary|
    ary << 0
    ary0 = (1..ary.size - 1).map{|i| ary[i - 1] - ary[i]}
    cnt += 1 if ary0.sort == ary0 && ary0.uniq == ary0
  }
  cnt
end
def A320510(n)
  (0..n).map{|i| f(i)}
end
p A320510(50)