A322447 Numbers k where Sum_{d | k} 1/rad(d) increases to a record.
1, 2, 4, 8, 12, 16, 24, 32, 48, 72, 96, 144, 192, 288, 384, 576, 864, 1152, 1728, 2304, 3456, 4608, 5184, 6912, 10368, 13824, 20736, 27648, 41472, 55296, 62208, 82944, 124416, 165888, 207360, 248832, 331776, 373248, 414720, 497664, 622080, 746496, 829440, 995328
Offset: 1
Keywords
Examples
The divisors of 12 are 1,2,3,4,6,12, so f(12) = 1 + (1/2) + (1/3) + (1/2) + (1/6) + (1/6) = 8/3, which exceeds f(n) for n = 1,...,11. Alternately, since f is multiplicative, f(12) = f(4)*f(3) = (1+2/2)*(1+1/3). f(207360) = f(2^9)*f(3^4)*f(5) = (11/2)*(7/3)*(6/5) = 15.4, which exceeds f(n) for n < 207360. (Note that this is the first value of the sequence that is divisible by 5; earlier values are all 3-smooth.)
Links
- Charlie Neder, Table of n, a(n) for n = 1..200
Programs
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Mathematica
rad[n_] := Times @@ (First@# & /@ FactorInteger@n); f[n_] := DivisorSum[n, 1/rad[#] &]; fm = 0; s = {}; Do[f1 = f[n]; If[f1 > fm, fm = f1; AppendTo[s, n]], {n, 1, 10^6}]; s (* Amiram Eldar, Dec 08 2018 *)
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PARI
rad(n) = factorback(factorint(n)[, 1]); \\ A007947 lista(nn) = {my(m=0, newm); for (n=1, nn, newm = sumdiv(n, d, 1/rad(d)); if (newm > m, m = newm; print1(n, ", ")););} \\ Michel Marcus, Dec 09 2018
Comments