A038770 Numbers divisible by at least one of their digits.
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 24, 25, 26, 28, 30, 31, 32, 33, 35, 36, 39, 40, 41, 42, 44, 45, 48, 50, 51, 52, 55, 60, 61, 62, 63, 64, 65, 66, 70, 71, 72, 75, 77, 80, 81, 82, 84, 85, 88, 90, 91, 92, 93, 95, 96, 99, 100, 101, 102
Offset: 1
Examples
35 is included because 5 is a divisor of 35, but 37 is not included because neither 3 nor 7 is a divisor of 37.
Links
- Reinhard Zumkeller, Table of n, a(n) for n = 1..10000
- Index entries for 10-automatic sequences
Programs
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Haskell
a038770 n = a038770_list !! (n-1) a038770_list = filter f [1..] where f u = g u where g v = v > 0 && (((d == 0 || r > 0) && g v') || r == 0) where (v',d) = divMod v 10; r = mod u d -- Reinhard Zumkeller, Jul 30 2015, Jun 19 2011
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Mathematica
Select[Range[120],MemberQ[Divisible[#,Cases[IntegerDigits[#],Except[0]]], True]&] (* Harvey P. Dale, Jun 20 2011 *) Select[Range[120],AnyTrue[#/DeleteCases[IntegerDigits[#],0],IntegerQ]&] (* Harvey P. Dale, Mar 29 2024 *)
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PARI
is(n)=my(v=vecsort(eval(Vec(Str(n))),,8));for(i=if(v[1],1,2),#v,if(n%v[i]==0,return(1)));0 \\ Charles R Greathouse IV, Jul 22 2011
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Python
def ok(n): return any(n%int(d) == 0 for d in str(n) if d != '0') print(list(filter(ok, range(1, 103)))) # Michael S. Branicky, May 20 2021
Formula
a(n) ~ n. - Charles R Greathouse IV, Jul 22 2011
Comments