cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A353537 Numbers whose abundancy index is larger than Pi^2/6.

Original entry on oeis.org

4, 6, 8, 10, 12, 14, 16, 18, 20, 24, 28, 30, 32, 36, 40, 42, 44, 45, 48, 50, 52, 54, 56, 60, 63, 64, 66, 68, 70, 72, 75, 76, 78, 80, 84, 88, 90, 92, 96, 98, 100, 102, 104, 105, 108, 110, 112, 114, 116, 120, 124, 126, 128, 130, 132, 135, 136, 138, 140, 144, 148, 150
Offset: 1

Views

Author

Amiram Eldar, Apr 25 2022

Keywords

Comments

The abundancy index of a number k is sigma(k)/k, where sigma is the sum of divisors function (A000203).
Pi^2/6 (A013661) is the asymptotic mean of the abundancy indices of the positive integers.
The least odd term is 45 and the least term that is coprime to 6 is 25025.
Davenport (1933) proved that sigma(k)/k possesses a continuous distribution function and that the asymptotic density of numbers with abundancy index that is larger than x exists for all x > 1 and is a continuous function of x. Therefore, this sequence has an asymptotic density.
The numbers of terms not exceeding 10^k, for k = 1, 2, ..., are 4, 41, 436, 4258, 42928, 428557, 4286145, 42864566, 428585795, 4286368677, 42861854540, ... Apparently, the asymptotic density is 0.4286... which means that the distribution of the abundancy indices is skewed with a positive nonparametric skew.

Examples

			4 is a term since sigma(4)/4 = 7/4 = 1.75 > Pi^2/6 = 1.644...
		

References

  • Harold Davenport, Über numeri abundantes, Sitzungsberichte der Preußischen Akademie der Wissenschaften, phys.-math. Klasse, No. 6 (1933), pp. 830-837.

Crossrefs

Programs

  • Mathematica
    Select[Range[150], DivisorSigma[-1, #] > Pi^2/6 &]
  • PARI
    isok(k) = sigma(k)/k > Pi^2/6; \\ Michel Marcus, Apr 25 2022

A385562 Numbers m such that (1/m) * Sum_{k=1..m} k/phi(k) sets a record value, where phi is the Euler totient function (A000010).

Original entry on oeis.org

1, 2, 4, 6, 12, 18, 22, 24, 30, 42, 60, 66, 72, 78, 84, 90, 114, 120, 150, 156, 180, 198, 210, 300, 330, 390, 420, 510, 546, 570, 600, 630, 750, 780, 840, 966, 990, 1122, 1170, 1200, 1260, 1410, 1470, 1560, 1596, 1620, 1650, 1680, 1806, 1830, 1890, 1980, 2100
Offset: 1

Views

Author

Amiram Eldar, Jul 03 2025

Keywords

Comments

Limit_{m->oo} (1/m) * Sum_{k=1..m} k/phi(k) = zeta(2)*zeta(3)/zeta(6) (A082695) (Sitaramachandrarao, 1985; Sándor et al., 2005). This sequence is infinite if this mean converges to the limit only from below.

References

  • József Sándor, Dragoslav S. Mitrinovic, and Borislav Crstici, Handbook of Number Theory I, Springer Science & Business Media, 2005, page 29.

Crossrefs

Programs

  • Mathematica
    seq[lim_] := Module[{s = {}, sum = 0, rm = 0, r}, Do[sum += k/EulerPhi[k]; r = sum/k; If[r > rm, rm = r; AppendTo[s, k]], {k, 1, lim}]; s]; seq[2500]
  • PARI
    list(lim) = {my(sm = 0, rm = 0, r); for(k = 1, lim, sm += k/eulerphi(k); r = sm/k; if(r > rm, rm = r; print1(k, ", ")));}

A342100 Abundant numbers k at which the ratio (number of abundant numbers in 1..k)/k reaches a new record high.

Original entry on oeis.org

12, 18, 20, 24, 40, 42, 56, 60, 72, 80, 84, 88, 90, 102, 104, 108, 112, 114, 354, 366, 368, 372, 380, 384, 392, 396, 400, 402, 464, 468, 476, 480, 492, 500, 504, 552, 560, 564, 572, 576, 580, 582, 650, 654, 836, 840, 945, 948, 952, 954, 1002, 2002, 2004, 2024
Offset: 1

Views

Author

Jon E. Schoenfield, Feb 27 2021

Keywords

Comments

Let rho(k) = (number of abundant numbers in 1..k)/k. According to A302991 ("Decimal expansion of the asymptotic density of abundant numbers"), lim_{k->infinity} rho(k) = 0.247619...
a(115) = 7254; rho(7254) = 1810/7254 = 0.2495175075820...
Conjecture: a(115) is the final term of this sequence.
This sequence is finite since rho(2212) > A302991 and therefore there is a number N such that abs(rho(n) - A302991) < eps for all n > N and for an arbitrarily small eps > 0. Therefore, the number of values of n for which rho(n) > rho(2212) is finite. - Amiram Eldar, Dec 06 2024

Examples

			k=12 is the 1st abundant number, so at k=12, rho(k) increases from 0 to 1/12 = 0.08333..., a record high, so a(1)=12.
k=18 is the 2nd abundant number, so at k=18, rho(k) reaches 2/18 = 1/9 = 0.11111..., the next record high, so a(2)=18.
k=20 is the 3rd abundant number, so at k=20, rho(k) reaches 3/20 = 0.15, the next record high, so a(3)=20.
k=24 is the 4th abundant number, so at k=24, rho(k) reaches 4/24 = 1/6 = 0.16666..., the next record high, so a(4)=24.
k=30 is the 5th abundant number, so at k=30, rho(k) again reaches 5/30 = 1/6; this is not a new record high, so 30 is not a term of the sequence.
		

Crossrefs

Cf. A005101 (abundant numbers), A302991, A330899.

Programs

  • Mathematica
    s = {}; c = 0; rm = 0; Do[If[DivisorSigma[1, n] > 2*n, c++; If[(r = c/n) > rm, rm = r; AppendTo[s, n]]], {n, 1, 10^4}]; s (* Amiram Eldar, Feb 28 2021 *)

Extensions

Keyword "fini" added by Amiram Eldar, Dec 06 2024

A385561 Numbers m such that (1/m) * Sum_{k=1..m} phi(k)/k is closer to 6/Pi^2 than it is for any number smaller than m, where phi is the Euler totient function (A000010).

Original entry on oeis.org

1, 2, 3, 4, 6, 10, 12, 16, 22, 28, 36, 66, 96, 100, 126, 156, 190, 330, 430, 540, 820, 876, 1086, 1422, 10596, 10836, 18096, 35796, 55786, 69336, 111100, 168666, 284650, 905950, 1482300, 1745590, 2405560, 2661310, 4023306, 5869956, 17454580, 25670646, 51305346, 79969618, 211025650, 622626790
Offset: 1

Views

Author

Amiram Eldar, Jul 03 2025

Keywords

Comments

6/Pi^2 is the asymptotic mean of phi(k)/k, i.e., lim_{m->oo} (1/m) * Sum_{k=1..m} phi(k)/k = 6/Pi^2 (Walfisz, 1963; Sándor et al., 2005).

References

  • József Sándor, Dragoslav S. Mitrinovic, and Borislav Crstici, Handbook of Number Theory I, Springer Science & Business Media, 2005, page 27.
  • Arnold Walfisz, Weylsche Exponentialsummen in der neueren Zahlentheorie, Berlin, 1963.

Crossrefs

Programs

  • Mathematica
    seq[lim_] := Module[{s = {}, sum = 0, dm = 1, d}, Do[sum += EulerPhi[k]/k; If[(d = Abs[sum/k - 6/Pi^2]) < dm, dm = d; AppendTo[s, k]], {k, 1, lim}]; s]; seq[10^5]
  • PARI
    list(lim) = {my(sm = 0, dm = 1, d); for(k = 1, lim, sm += eulerphi(k)/k; d = abs(sm/k - 6/Pi^2); if(d < dm, dm = d; print1(k, ", ")));}
Showing 1-4 of 4 results.