A333448 Smallest positive divisibility coefficient of A045572(n).
1, 1, 5, 1, 10, 4, 12, 2, 19, 7, 19, 3, 28, 10, 26, 4, 37, 13, 33, 5, 46, 16, 40, 6, 55, 19, 47, 7, 64, 22, 54, 8, 73, 25, 61, 9, 82, 28, 68, 10, 91, 31, 75, 11, 100, 34, 82, 12, 109, 37, 89, 13, 118, 40, 96, 14, 127, 43, 103, 15, 136, 46, 110, 16, 145, 49, 117
Offset: 1
Keywords
Examples
For example, let us check whether 21 is divisible by 7. First, we take off the last digit, 1. Since 7 is the third member of A045572, its divisibility coefficient is the third member of this sequence, namely 5. Then we multiply 5 times 1 to obtain 5, and we add it to the original number without the last digit, in our case, 2. We get 7, and since it is clearly divisible by 7, so is 21.
Links
- Michael De Vlieger, Table of n, a(n) for n = 1..10000
- Index entries for linear recurrences with constant coefficients, signature (0,0,0,2,0,0,0,-1).
Crossrefs
Cf. A045572.
Programs
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Mathematica
Array[# - (# Mod[PowerMod[#, 3, 10], 10] - 1)/10 &[1/2*(5*# + Mod[3*# + 2, 4] - 4)] &, 67] (* Michael De Vlieger, Oct 05 2020 *)
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PARI
lista(nn) = {for (n=1, nn, if (gcd(n,10) == 1, my(m=n % 10, k=n\10, x); if (m == 1, x = 9*k+1); if (m == 3, x = 3*k+1); if (m == 7, x = 7*k+5); if (m == 9, x = k+1); print1(x, ", ");););} \\ Michel Marcus, May 04 2020
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Python
def a(n): u = 10*((n-1) // 4) + [1, 3, 7, 9][(n-1) % 4] return pow(10, -1, u) + (u == 1) print(*(a(i) for i in range(1,101)), sep=", ") # Ely Golden, Mar 27 2024
Formula
The sequence can be defined piecewise: 9m+1 for numbers of the form 10m+1; 3m+1 for numbers of the form 10m+3; 7m+5 for numbers of the form 10m+7 and m+1 for numbers of the form 10m+9.
From Lorenzo Sauras Altuzarra, Sep 29 2020: (Start)
a(n) = 1/10 - (1 - 2*(floor((n + 1)/4) + n))*(1 - (1 + (floor(16*9^n/205) mod 9))/10).
a(n) = b(n) - (((b(n) mod 10)^3 mod 10)*b(n) - 1)/10, where b(n) = A045572(n). (End)
Extensions
More terms from Michel Marcus, May 04 2020
Comments