A064415 a(1) = 0, a(n) = iter(n) if n is even, a(n) = iter(n)-1 if n is odd, where iter(n) = A003434(n) = smallest number of iterations of Euler totient function phi needed to reach 1.
0, 1, 1, 2, 2, 2, 2, 3, 2, 3, 3, 3, 3, 3, 3, 4, 4, 3, 3, 4, 3, 4, 4, 4, 4, 4, 3, 4, 4, 4, 4, 5, 4, 5, 4, 4, 4, 4, 4, 5, 5, 4, 4, 5, 4, 5, 5, 5, 4, 5, 5, 5, 5, 4, 5, 5, 4, 5, 5, 5, 5, 5, 4, 6, 5, 5, 5, 6, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 4, 6, 6, 5, 6, 5, 5, 6, 6, 5, 5, 6, 5, 6, 5, 6, 6, 5, 5, 6, 6, 6, 6, 6, 5
Offset: 1
Keywords
Links
- Reinhard Zumkeller, Table of n, a(n) for n = 1..10000
- Paul Erdős, Andrew Granville, Carl Pomerance and Claudia Spiro, On the normal behavior of the iterates of some arithmetic functions, Analytic number theory, Birkhäuser Boston, 1990, pp. 165-204.
- Paul Erdos, Andrew Granville, Carl Pomerance and Claudia Spiro, On the normal behavior of the iterates of some arithmetic functions, Analytic number theory, Birkhäuser Boston, 1990, pp. 165-204. [Annotated copy with A-numbers]
Crossrefs
Programs
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Haskell
a064415 1 = 0 a064415 n = a003434 n - n `mod` 2 -- Reinhard Zumkeller, Sep 18 2011
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PARI
A003434(n)=for(k=0, n, n>1 || return(k); n=eulerphi(n)); a(n) = if( n<=2, n-1, A003434(n) - (n%2) ); vector(200, n, a(n)) \\ Joerg Arndt, Apr 08 2014
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PARI
A064415(n) = if(!bitand(n,n-1),valuation(n,2),A064415(n-(n/vecmax(factor(n)[, 1])))); \\ Antti Karttunen, May 13 2020
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PARI
A064415(n) = if(1==n, 0, if(isprime(n), 1+A064415(n>>1), my(f=factor(n)); (apply(A064415, f[, 1])~ * f[, 2]))); \\ Antti Karttunen, May 13 2020
Formula
For all integers m >0 and n>0 a(m*n)=a(m)+a(n). The function a(n) is completely additive. The smallest integer q which satisfy the equation a(q)=n is 2^q, the greatest is 3^q. For all integers n>0, the counter image off n, a^-1(n) is finite.
a(1) = 0 and a(n) = A054725(n) for n>=2. - Joerg Arndt, Apr 08 2014, A-number corrected by Antti Karttunen, May 13 2020
From Antti Karttunen, May 13 2020: (Start)
a(1) = 0, a(2) = 1 and for n > 2, a(n) = sum(p | n, a(p-1)), where sum is over all primes p that divide n, with multiplicity. (Cf. A054725).
a(1) = 0, a(2) = 1 and a(p) = 1 + a((p-1)/2) if p is an odd prime and a(n*m) = a(n) + a(m) if m,n > 1. [From above formula, 1+ compensates for the "lost" 2]
a(n) = A007814(A309243(n)). [From Rémy Sigrist's conjecture in the latter sequence. This reduces to a(n) = sum(p|n, a(p-1)) formula above, thus holds also]
If A209229(n) = 1 [when n is a power of 2], a(n) = A007814(n), otherwise a(n) = a(n-A052126(n)) = a(A171462(n)). [From the definition in the comments]
a(2^k) = a(3^k) = k.
(End)
Extensions
More terms from David Wasserman, Jul 22 2002
Definition corrected by Reinhard Zumkeller, Sep 18 2011
Comments