cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A336443 Primitive terms of A336442: terms k of A336442 such that none of the proper divisors of k are in A336442.

Original entry on oeis.org

60, 140, 210, 315, 462, 504, 616, 693, 728, 770, 792, 819, 910, 936, 990, 1001, 1092, 1144, 1170, 1287, 1430, 1530, 1683, 1716, 1870, 1989, 2090, 2142, 2145, 2210, 2244, 2431, 2448, 2470, 2508, 2618, 2652, 2717, 2805, 2926, 2964, 2992, 3094, 3135, 3230, 3315
Offset: 1

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Author

Amiram Eldar, Jul 21 2020

Keywords

Comments

Any term of A336442 is a multiple of at least one term of this sequence.

Examples

			60 is a term since it is a term of A336442 but none of its proper divisors are in A336442.
120 is not a term: although it is in A336442, it is a multiple of 60 which is also a term of A336442.
		

Crossrefs

Analogous to A302022 as A336442 is analogous to A005279.

Programs

  • Mathematica
    divQ[n_] := AnyTrue[Subsets[Divisors[n], {3}], And @@ CoprimeQ @@@ Subsets[#, {2}] && #[[3]] < 2 #[[1]] &]; primQ[n_] := divQ[n] && AllTrue[Most[Divisors[n]], ! divQ[#] &]; Select[Range[3333], primQ]

A333966 Positive integers where the number of triples of divisors (d1, d2, d3) such that d1 < d2 < d3 < 2*d1 and each pair of these divisors is pairwise coprime, sets a new record.

Original entry on oeis.org

1, 60, 280, 420, 840, 1260, 2520, 6930, 9240, 13860, 27720, 55440, 60060, 120120, 180180, 240240, 360360, 720720, 1021020, 1801800, 2042040, 2282280, 2762760, 3063060, 4084080, 4564560, 6126120, 12252240, 19399380, 24504480, 30630600, 36756720, 38798760, 58198140, 77597520
Offset: 1

Views

Author

David A. Corneth, Jul 22 2020

Keywords

Comments

Records are 0, 1, 2, 3, 4, 5, 8, 9, 11, 13, 19, ...
Are terms > 4564560 products of primorials (cf. A025487)? Terms 4564560 < k <= 54765047434897800 are.
In a triple (d1, d2, d3) such that lcm(d1, d2, d3) = d1*d2*d2 <= k we must have d1^3 < k. Proof: Suppose d1^3 >= n. Then d1 * d2 * d3 > n since d2 > d1 and d3 > d1. Since any pair is coprime d1 * d2 * d3 = LCM(d1,d2,d3) is a divisor of n. A contradiction. - David A. Corneth and Amiram Eldar, Jul 28 2020

Examples

			280 has two such divisor triples; (4, 5, 7) and (5, 7, 8) and no number less than 280 has at least two such triples so 280 is in the sequence.
		

Crossrefs

Programs

  • PARI
    upto(n) = { v = vectorsmall(n); for(i = 2, sqrtnint(n, 3), for(j = i + 1, min(sqrtint(n \ i), 2*i-2), g = gcd(i, j); if(g == 1, l = i * j / g; for(k = j + 1, min(2*i-1, n \ (i*j)), if(gcd(l, k) == 1, p = l*k; forstep(m = p, n, p, v[m]++ ); t++ ))))); my(res=List(1), r=v[1]); for(i=2, #v, if(v[i]>r, r=v[i]; listput(res,i))); res }
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