cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A381486 Number of labeled histories for rooted ternary trees with 2n+1 leaves if simultaneous trifurcations are allowed.

Original entry on oeis.org

1, 1, 10, 420, 43960, 9347800, 3513910400, 2131249120000, 1952028782704000, 2568150610833808000, 4666919676058159520000, 11351087418588355518080000, 36008099327884173922432000000, 145785514242304854141480256000000, 739598808823839440680777500928000000, 4627885522642342503645368137231360000000
Offset: 0

Views

Author

Noah A Rosenberg, Feb 25 2025

Keywords

Comments

a(n) is also the number of single-elimination sports tournament schedules possible for 2n+1 teams if matches involve three teams, arbitrarily many arenas are available, and labeled teams have been specified, but the bracket of matches has not been specified.

Examples

			Consider 7 named players in a sport in which players compete 3 at a time (e.g. the television gameshow "Jeopardy!"). The number of ways a single-elimination tournament can be arranged, if simultaneous matches can take place, is a(3)=420. Three of these 420 are: (1) A, B, and C play; the winner plays against D and E; the winner plays against F and G. (2) D, E, and F play; the winner plays against A and B; the winner plays against C and G. (3) A, B, and C play simultaneous with D, E, and F; the winners of these matches play against G.
		

Crossrefs

Cf. A317059 for binary rather than ternary trees, A339411 if simultaneity is disallowed.

Programs

  • Maple
    a:= proc(n) option remember; `if`(n=0, 1, add((2*n+1)!/
          (i!*6^i*(2*n+1-3*i)!)*a(n-i), i=1..(2*n+1)/3))
        end:
    seq(a(n), n=0..15);  # Alois P. Heinz, Feb 25 2025

Formula

a(n) = Y(2n+1), where Y(n) = Sum_{i=1..floor(n/3)} (n!/(i!*6^i*(n-3*i)!))*Y(n-2*i), with Y(1)=1.

A381536 Number of labeled histories for rooted 4-furcating trees with 3n+1 leaves if simultaneous 4-furcations are not allowed.

Original entry on oeis.org

1, 1, 35, 7350, 5255250, 9564555000, 37072215180000, 271183254041700000, 3430468163627505000000, 70238835650273164875000000, 2210064963735845132791875000000, 102493972758213553878355995000000000, 6769214430816214165896021689775000000000, 618638506832293812621237422228537250000000000
Offset: 0

Views

Author

Noah A Rosenberg, Feb 26 2025

Keywords

Crossrefs

Programs

  • Maple
    a:= n-> (3*n+1)!/24^n*mul(3*i-2, i=1..n):
    seq(a(n), n=0..13);  # Alois P. Heinz, Feb 26 2025

Formula

a(n) = ((3*n+1)!/24^n) * Product_{i=1..n} (3*i-2).

A381866 Number of labeled histories for rooted 5-furcating trees with 4n+1 leaves if simultaneous 5-furcations are not allowed.

Original entry on oeis.org

1, 1, 126, 162162, 1003458456, 20419376121144, 1084881453316380720, 128835096988586792403600, 30577206578883234961900809600, 13328512616115465470187677202211200, 9988360697491697592427704919982668857600, 12203369577406758958826880335333105520792518400
Offset: 0

Views

Author

Noah A Rosenberg, Mar 08 2025

Keywords

Crossrefs

Cf. A006472, A339411, A381536 for bifurcating, trifurcating, and quadfurcating trees; A381533 if simultaneity is allowed.
Cf. A007696.

Programs

  • Mathematica
    a[n_]:=((4*n+1)!/120^n)*Product[(4*i-3),{i,n}]; Array[a,11,0] (* Stefano Spezia, Mar 09 2025 *)

Formula

a(n) = ((4*n+1)!/120^n) * Product_{i=1..n} (4*i-3).
a(n) = Gamma(4*n+2)*Gamma(n+1/4)/(30^n*Gamma(1/4)). - Stefano Spezia, Mar 09 2025
a(n) = A007696(n)*(4*n+1)!/120^n. - Alois P. Heinz, Mar 10 2025
Showing 1-3 of 3 results.