A340013 The prime gap, divided by two, which surrounds n!.
1, 3, 7, 4, 6, 27, 15, 11, 7, 15, 45, 10, 45, 38, 45, 39, 95, 30, 31, 52, 93, 102, 95, 48, 22, 84, 127, 54, 94, 40, 19, 145, 87, 129, 49, 22, 85, 68, 66, 88, 90, 78, 146, 95, 156, 78, 71, 79, 225, 60, 65, 175, 66, 305, 192, 196, 215, 205, 420, 101, 186, 213, 160
Offset: 3
Keywords
Examples
For a(1), there are no positive primes which surround 1!. Therefore a(1) is undefined. For a(2), there are two contiguous primes {2, 3} with 2 being 2!. The prime gap is 1. However, the two primes do not surround 2!, so a(2) is undefined. For a(3), the following set of numbers, {5, 6, 7}, with 3! being in the middle. The prime gap is 2; therefore, a(3) = 1. For a(4), the following set of numbers, {23, 24, 25, 26, 27, 28, 29} with 4! in between the two primes 23 & 29. The prime gap is 6, so a(4) = 3.
Links
- Robert Israel, Table of n, a(n) for n = 3..607
Programs
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Maple
a:= n-> (f-> (nextprime(f-1)-prevprime(f+1))/2)(n!): seq(a(n), n=3..70); # Alois P. Heinz, Jan 09 2021
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Mathematica
a[n_] := (NextPrime[n!, 1] - NextPrime[n!, -1])/2; Array[a, 70, 3]
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PARI
a(n) = (nextprime(n!+1) - precprime(n!-1))/2; \\ Michel Marcus, Jan 11 2021
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Python
from sympy import factorial, nextprime, prevprime def A340013(n): f = factorial(n) return (nextprime(f)-prevprime(f))//2 # Chai Wah Wu, Jan 23 2021
Comments