cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A348615 Number of non-alternating permutations of {1...n}.

Original entry on oeis.org

0, 0, 0, 2, 14, 88, 598, 4496, 37550, 347008, 3527758, 39209216, 473596070, 6182284288, 86779569238, 1303866853376, 20884006863710, 355267697410048, 6397563946377118, 121586922638606336, 2432161265800164950, 51081039175603191808, 1123862030028821404198
Offset: 0

Views

Author

Gus Wiseman, Nov 03 2021

Keywords

Comments

A sequence is alternating if it is alternately strictly increasing and strictly decreasing, starting with either.
Also permutations of {1...n} matching the consecutive patterns (1,2,3) or (3,2,1). Matching only one of these gives A065429.

Examples

			The a(4) = 14 permutations:
  (1,2,3,4)  (3,1,2,4)
  (1,2,4,3)  (3,2,1,4)
  (1,3,4,2)  (3,4,2,1)
  (1,4,3,2)  (4,1,2,3)
  (2,1,3,4)  (4,2,1,3)
  (2,3,4,1)  (4,3,1,2)
  (2,4,3,1)  (4,3,2,1)
		

Crossrefs

The complement is counted by A001250, ranked by A333218.
The complementary version for compositions is A025047, ranked by A345167.
A directed version is A065429, complement A049774.
The version for compositions is A345192, ranked by A345168.
The version for ordered factorizations is A348613, complement A348610.
A345165 counts partitions w/o an alternating permutation, ranked by A345171.
A345170 counts partitions w/ an alternating permutation, ranked by A345172.
A348379 counts factorizations with an alternating permutation.
A348380 counts factorizations without an alternating permutation.

Programs

  • Maple
    b:= proc(u, o) option remember;
          `if`(u+o=0, 1, add(b(o-1+j, u-j), j=1..u))
        end:
    a:= n-> n!-`if`(n<2, 1, 2)*b(n, 0):
    seq(a(n), n=0..30);  # Alois P. Heinz, Nov 04 2021
  • Mathematica
    wigQ[y_]:=Or[Length[y]==0,Length[Split[y]] ==Length[y]&&Length[Split[Sign[Differences[y]]]]==Length[y]-1];
    Table[Length[Select[Permutations[Range[n]],!wigQ[#]&]],{n,0,6}]
  • Python
    from itertools import accumulate, count, islice
    def A348615_gen(): # generator of terms
        yield from (0,0)
        blist, f = (0,2), 1
        for n in count(2):
            f *= n
            yield f - (blist := tuple(accumulate(reversed(blist),initial=0)))[-1]
    A348615_list = list(islice(A348615_gen(),40)) # Chai Wah Wu, Jun 09-11 2022

Formula

a(n) = n! - A001250(n).