A351113 Sum of the balanced numbers dividing n.
1, 3, 4, 3, 1, 12, 1, 3, 4, 3, 1, 24, 1, 17, 19, 3, 1, 12, 1, 3, 4, 3, 1, 24, 1, 3, 4, 17, 1, 57, 1, 3, 4, 3, 36, 24, 1, 3, 4, 3, 1, 68, 1, 3, 19, 3, 1, 24, 1, 3, 4, 3, 1, 12, 1, 73, 4, 3, 1, 69, 1, 3, 4, 3, 1, 12, 1, 3, 4, 122, 1, 24, 1, 3, 19, 3, 1, 90, 1, 3, 4, 3, 1, 80
Offset: 1
Keywords
Examples
a(4) = 3; the balanced divisors of 4 are 1 and 2 and 1+2 = 3. a(5) = 1; 1 is the only balanced divisor of 5. a(6) = 12; the balanced divisors of 6 are 1,2,3,6 and 1+2+3+6 = 12.
Links
- Antti Karttunen, Table of n, a(n) for n = 1..20000
Crossrefs
Programs
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Mathematica
a[n_] := DivisorSum[n, # &, Divisible[DivisorSigma[1, #], EulerPhi[#]] &]; Array[a, 100] (* Amiram Eldar, Feb 01 2022 *)
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PARI
a(n) = sumdiv(n, d, if (!(sigma(d) % eulerphi(d)), d)); \\ Michel Marcus, Feb 01 2022
Formula
a(n) = Sum_{d|n, phi(d)|sigma(d)} d.
a(n) = Sum_{d|n} d * A351114(d).
a(n) = sigma(n) - Sum_{d|n} d * sign(sigma(d) mod phi(d)).
Comments