A352264 Integers that need 6 iterations of the map x->A352172(x) to reach 1.

377, 737, 773, 1377, 1737, 1773, 3077, 3177, 3707, 3717, 3770, 3771, 3889, 3898, 3988, 4689, 4698, 4869, 4896, 4968, 4986, 5677, 5767, 5776, 6489, 6498, 6577, 6668, 6686, 6757, 6775, 6849, 6866, 6894, 6948, 6984, 7037, 7073, 7137, 7173, 7307, 7317, 7370, 7371, 7567, 7576

Offset: 1

Author

Michel Marcus, Mar 10 2022

Keywords

• nonn
• base

Examples

			377 -> 3176523 -> 54010152000 -> 8000000 -> 512 -> 1000 -> 1.
		

Crossrefs

Cf. A352172. Subsequence of A351876.

Cf. A352260, A352261, A352262, A352263, A352265, A352266, A352267, A352268.

Programs

Mathematica

f[n_] := (Times @@ Select[IntegerDigits[n], # > 1 &])^3; q[n_, len_] := (v = Nest[f, n, len - 1]) != 1 && f[v] == 1; Select[Range[7576], q[#, 6] &] (* Amiram Eldar, Mar 10 2022 *)

PARI

f(n) = vecprod(apply(x->x^3, select(x->(x>1), digits(n)))); \\ A352172
isok6(n) = {for (k=1, 6, n = f(n); if ((n==1), return(k==6)););}

Python

from math import prod
def A352172(n): return prod(int(d)**3 for d in str(n) if d != '0')
def ok(x, iters=6):
    i = 0
    while i < iters and x != 1: i, x = i+1, A352172(x)
    return i == iters and x == 1
print([k for k in range(7577) if ok(k)]) # Michael S. Branicky, Mar 10 2022