A352412 E.g.f.: 2*x / LambertW( 2*x/(1-x) ).

1, 1, -4, 20, -224, 3392, -67232, 1629728, -46799104, 1552143104, -58386807296, 2455954797056, -114222622662656, 5819845970653184, -322384671892123648, 19290013218140254208, -1239886482366130946048, 85200320552417960394752

Offset: 0

Author

Paul D. Hanna, Mar 15 2022

Keywords

• sign

Comments

An interesting property of this e.g.f. A(x) is that the sum of coefficients of x^k, k=0..n, in A(x)^n equals zero, for n > 1.

Examples

			E.g.f.: A(x) = 1 + x - 4*x^2/2! + 20*x^3/3! - 224*x^4/4! + 3392*x^5/5! - 67232*x^6/6! + 1629728*x^7/7! - 46799104*x^8/8! + ...
such that A(x) = (1-x) * exp(2*x/A(x)), where
exp(2*x/A(x)) = 1 + 2*x + 20*x^3/3! - 144*x^4/4! + 2672*x^5/5! - 51200*x^6/6! + 1271328*x^7/7! - 36628480*x^8/8! + ...
Related series.
The e.g.f. A(x) satisfies A( x/(exp(-2*x) + x) ) = 1/(exp(-2*x) + x), where
1/(exp(-2*x) + x) = 1 + x - 2*x^2/2! - 10*x^3/3! + 24*x^4/4! + 312*x^5/5! - 560*x^6/6! + ... + A336958(n)*(-x)^n/n! + ...
Related table.
Another defining property of the e.g.f. A(x) is illustrated here.
The table of coefficients of x^k/k! in A(x)^n begins:
n=1: [1, 1, -4,   20,  -224, 3392, -67232, 1629728, ...];
n=2: [1, 2, -6,   16,  -192, 2944, -58880, 1434752, ...];
n=3: [1, 3, -6,   -6,   -48, 1296, -29664,  776544, ...];
n=4: [1, 4, -4,  -40,    88,  128,  -7424,  263936, ...];
n=5: [1, 5,  0,  -80,   120,  280,   -320,   38720, ...];
n=6: [1, 6,  6, -120,   -24, 1872,  -3312,     768, ...];
n=7: [1, 7, 14, -154,  -392, 4424,  -3920,  -22288, ...];
...
from which we can illustrate that the partial sum of coefficients of x^k, k=0..n, in A(x)^n equals zero, for n > 1, as follows:
n=1: 2 = 1 + 1;
n=2: 0 = 1 + 2 + -6/2!;
n=3: 0 = 1 + 3 + -6/2! +   -6/3!;
n=4: 0 = 1 + 4 + -4/2! +  -40/3! +   88/4!;
n=5: 0 = 1 + 5 +  0/2! +  -80/3! +  120/4! +  280/5!;
n=6: 0 = 1 + 6 +  6/2! + -120/3! +  -24/4! + 1872/5! + -3312/6!;
n=7: 0 = 1 + 7 + 14/2! + -154/3! + -392/4! + 4424/5! + -3920/6! + -22288/7!;
...
		

Crossrefs

Cf. A352410, A352411, A352448, A336958.

Programs

PARI

{a(n) = n!*polcoeff( x/serreverse( x/(exp(-2*x  +x^2*O(x^n)) + x) ),n)}
for(n=0,30,print1(a(n),", "))

PARI

my(x='x+O('x^30)); Vec(serlaplace(2*x/lambertw(2*x/(1-x)))) \\ Michel Marcus, Mar 17 2022

Formula

E.g.f. A(x) = Sum_{n>=0} a(n)*x^n/n! satisfies:

(1) A(x) = 2*x / LambertW( 2*x/(1-x) ).

(2) A(x) = (1-x) * exp( 2*x/A(x) ).

(3) A(x) = 2*x / log( A(x)/(1-x) ).

(4) A( x/(exp(-2*x) + x) ) = 1/(exp(-2*x) + x).

(5) A(x) = x / Series_Reversion( x/(exp(-2*x) + x) ).

(6) Sum_{k=0..n} [x^k] A(x)^n = 0, for n > 1.

(7) [x^(n+1)/(n+1)!] A(x)^n = -(-2)^(n+1) * n for n >= (-1).

a(n) ~ (-1)^(n+1) * exp(-1) * sqrt(2) * (2 - exp(-1))^(n - 1/2) * n^(n-1). - Vaclav Kotesovec, Mar 15 2022