A354218 Records in A076978, divided by 2.
1, 3, 15, 105, 1155, 1365, 19635, 23205, 636405, 10555545, 24484845, 869107785, 14797252681546335, 92442344345566215, 40334203530676690635, 1451417351374223318085, 6087255082617244520985, 469256253416014832182075245585, 1519012498286389398934397206158552189345
Offset: 1
Keywords
Links
- Hugo Pfoertner, Table of n, a(n) for n = 1..52.
Programs
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Mathematica
1/2*Union@ FoldList[Max, Array[Times @@ FactorInteger[Times @@ Range[#1 + 1, #2 - 1]][[All, 1]] & @@ Map[Prime, # + {0, 1}] &, 180, 2]] (* Michael De Vlieger, May 20 2022 *)
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PARI
a354218(maxterm) = {my(mp=0,pp=3); forprime(p=5,oo, my(L=List());for(j=pp+1,p-1, my(f=factor(j), nf=#f~); for(k=1,nf, listput(~L,f~[1,k]))); listsort(L,1); my(mpp=prod(k=1,#L,L[k])); if(mpp>mp, if(mpp<2*maxterm, print1(mpp/2,", "); mp=mpp, return)); pp=p)}; a354218(10^75)
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Python
from sympy import sieve as p, primefactors def A076978_halfen(n): # for all integers n > 1 result = 1 for composites in range(p[n]+1, p[n+1]): for primefactor in primefactors(composites): if result % primefactor != 0: result *= primefactor return result//2 A354218 = [1] for n in range(2,180): if A076978_halfen(n) > A354218[-1]: A354218.append(A076978_halfen(n)) print(A354218) # Karl-Heinz Hofmann, May 20 2022