A359325 Number of divisors of 6*n-3 of form 6*k+5.
0, 0, 1, 0, 0, 1, 0, 1, 1, 0, 0, 1, 1, 0, 1, 0, 1, 2, 0, 0, 1, 0, 1, 1, 0, 1, 1, 2, 0, 1, 0, 0, 2, 0, 1, 1, 0, 1, 2, 0, 0, 1, 2, 1, 1, 0, 0, 2, 0, 1, 1, 0, 2, 1, 0, 0, 1, 2, 0, 2, 1, 1, 2, 0, 0, 1, 0, 1, 1, 0, 1, 2, 2, 0, 1, 0, 1, 2, 0, 1, 2, 0, 2, 1, 0, 0, 1, 2, 1, 1
Offset: 1
Links
- Seiichi Manyama, Table of n, a(n) for n = 1..10000
Programs
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Mathematica
a[n_] := DivisorSum[6*n-3, 1 &, Mod[#, 6] == 5 &]; Array[a, 100] (* Amiram Eldar, Aug 16 2023 *)
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PARI
a(n) = sumdiv(6*n-3, d, d%6==5);
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PARI
my(N=100, x='x+O('x^N)); concat([0, 0], Vec(sum(k=1, N, x^(3*k)/(1-x^(6*k-1)))))
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PARI
my(N=100, x='x+O('x^N)); concat([0, 0], Vec(sum(k=1, N, x^(5*k-2)/(1-x^(6*k-3)))))
Formula
a(n) = A319995(6*n-3).
G.f.: Sum_{k>0} x^(3*k)/(1 - x^(6*k-1)).
G.f.: Sum_{k>0} x^(5*k-2)/(1 - x^(6*k-3)).