cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 36 results. Next

A361118 a(n) = gcd(A360519(n), A360519(n+1)).

Original entry on oeis.org

1, 2, 5, 7, 3, 4, 5, 11, 3, 2, 7, 11, 3, 5, 2, 11, 13, 3, 4, 7, 13, 5, 2, 17, 7, 9, 2, 13, 17, 3, 2, 19, 5, 3, 4, 11, 17, 5, 2, 23, 3, 19, 4, 13, 3, 5, 2, 29, 3, 31, 2, 7, 3, 37, 2, 17, 3, 41, 2, 5, 23, 7, 12, 5, 29, 7, 2, 3, 43, 5, 2, 3, 47, 5, 2, 3, 7, 19, 2
Offset: 1

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Examples

			a(7) = gcd(A360519(7), A360519(8)) = gcd(20, 55) = 5.
		

Crossrefs

Cf. A360519.

Programs

  • PARI
    See Links section.

Formula

a(n) > 1 for any n > 1.

A361103 a(n) = k such that A360519(k) = A361102(n), or -1 if A361102(n) never appears in A360519.

Original entry on oeis.org

1, 2, 3, 6, 11, 14, 10, 7, 5, 16, 19, 28, 20, 23, 9, 24, 4, 27, 32, 18, 15, 31, 36, 34, 40, 35, 39, 30, 44, 68, 8, 52, 42, 48, 64, 51, 26, 22, 72, 56, 41, 47, 76, 55, 46, 43, 12, 80, 60, 59, 63, 38, 84, 49, 88, 87, 21, 92, 50, 96, 33, 91, 67, 13, 71, 95, 100, 53, 104, 99, 75, 54, 112, 108
Offset: 0

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Comments

Conjectured to be a permutation of the natural numbers (and if so, -1 will never appear). See A361104 for the putative inverse permutation.

Crossrefs

A361107 Records in A360519.

Original entry on oeis.org

1, 6, 10, 35, 55, 77, 99, 143, 221, 235, 301, 329, 371, 391, 497, 511, 623, 1243, 1253, 1379, 1393, 1799, 1837, 1969, 2513, 2629, 3353, 3493, 3601, 3983, 6259, 8063, 10417, 12991, 13453, 16003, 17413, 21967, 23089, 27049, 32329, 33737, 40079, 60073, 70103, 73411, 79673, 105131, 116677, 117799, 119933, 124619, 128227, 130537, 149083
Offset: 1

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Crossrefs

A361109 After A360519(n) has been found, a(n) is the smallest member of C (A361102) that is missing from A360519.

Original entry on oeis.org

6, 10, 12, 12, 12, 14, 14, 14, 14, 14, 15, 15, 15, 22, 22, 24, 24, 24, 26, 26, 26, 26, 26, 26, 26, 26, 26, 38, 38, 38, 38, 44, 44, 44, 44, 46, 46, 46, 46, 52, 52, 52, 52, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54, 54
Offset: 1

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Examples

			After we have calculated A360519(4) = 35, the smallest term of C that is missing from A360519 is 12, so a(4) = 12.
		

Crossrefs

Programs

  • PARI
    See Links section.

Extensions

More terms from Rémy Sigrist, Mar 03 2023

A361111 The binary expansion of a(n) specifies which primes divide A360519(n).

Original entry on oeis.org

0, 3, 5, 12, 10, 3, 5, 20, 18, 3, 9, 24, 18, 6, 5, 17, 48, 34, 3, 9, 40, 36, 7, 65, 72, 10, 3, 33, 96, 66, 11, 129, 132, 6, 3, 17, 80, 68, 5, 257, 258, 130, 129, 33, 34, 6, 13, 513, 514, 1026, 1025, 9, 14, 2050, 2049, 65, 66, 4098, 4097, 5, 260, 264, 11, 7
Offset: 1

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Examples

			A360519(6) = 12, which is divisible by 2, 3, but not 5, 7, 11, ... So we write down 1, 1, 0, 0, 0, .... Thus a(6) has binary expansion ...00011, and so a(6) = 3.
		

Crossrefs

Programs

  • PARI
    See Links section.

Formula

a(n) = A087207(A360519(n)). - Rémy Sigrist, Mar 03 2023

Extensions

More terms from Rémy Sigrist, Mar 03 2023

A361119 a(n) is the least prime factor of A360519(n) with a(1) = 1.

Original entry on oeis.org

1, 2, 2, 5, 3, 2, 2, 5, 3, 2, 2, 7, 3, 3, 2, 2, 11, 3, 2, 2, 7, 5, 2, 2, 7, 3, 2, 2, 13, 3, 2, 2, 5, 3, 2, 2, 11, 5, 2, 2, 3, 3, 2, 2, 3, 3, 2, 2, 3, 3, 2, 2, 3, 3, 2, 2, 3, 3, 2, 2, 5, 7, 2, 2, 5, 7, 2, 2, 3, 5, 2, 2, 3, 5, 2, 2, 3, 7, 2, 2, 3, 5, 2, 2, 7, 5
Offset: 1

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Comments

See A361120 for the greatest prime factors.

Examples

			A360519(2) = 2*3 so a(2) = 2.
		

Crossrefs

Programs

  • PARI
    See Links section.

Formula

a(n) = A020639(A360519(n)).

A361120 a(n) is the greatest prime factor of A360519(n) with a(1) = 1.

Original entry on oeis.org

1, 3, 5, 7, 7, 3, 5, 11, 11, 3, 7, 11, 11, 5, 5, 11, 13, 13, 3, 7, 13, 13, 5, 17, 17, 7, 3, 13, 17, 17, 7, 19, 19, 5, 3, 11, 17, 17, 5, 23, 23, 19, 19, 13, 13, 5, 7, 29, 29, 31, 31, 7, 7, 37, 37, 17, 17, 41, 41, 5, 23, 23, 7, 5, 29, 29, 7, 3, 43, 43, 5, 11, 47
Offset: 1

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Comments

See A361119 for the least prime factors.

Examples

			A360519(2) = 2*3 so a(2) = 3.
		

Crossrefs

Programs

  • PARI
    See Links section.

Formula

a(n) = A006530(A360519(n)).

A361128 Let b = A360519; let Lg = gcd(b(n-1),b(n)), Rg = gcd(b(n),b(n+1)); let L(n) = prod_{primes p|Lg} p-part of b(n), R(n) = prod_{primes p|Rg} p-part of b(n), M(n) = b(n)/(L(n)*R(n)); sequence gives L(n).

Original entry on oeis.org

1, 2, 5, 7, 3, 4, 5, 11, 9, 2, 7, 11, 3, 5, 2, 11, 13, 3, 4, 7, 13, 5, 2, 17, 7, 9, 2, 13, 17, 3, 2, 19, 5, 3, 4, 11, 17, 25, 2, 23, 3, 19, 4, 13, 3, 5, 2, 29, 3, 31, 8, 7, 3, 37, 4, 17, 3, 41, 16, 5, 23, 7, 12, 5, 29, 49, 2, 3, 43, 25, 2, 3, 47, 5, 8, 3, 7, 19, 2, 27, 5, 31
Offset: 2

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Comments

The p-part of a number k is the highest power of p that divides k. For example, the 2-part of 24 is 8, the 3-part is 3.
One can think of A360519 as a chain of circles, each circle linked to its neighbors to the left and the right. The n-th term b(n) = A360519(n) is a product L(n)*M(n)*R(n), where L(n) is the part of b(n) sharing primes with the term to the left, R(n) the part sharing primes with the term to the right, and M(n) is the rest of b(n).
By definition of A360519, the set of primes in L(n) is disjoint from the primes in R(n).

Crossrefs

Programs

  • Maple
    # Suppose bW is a list of the terms of A360519.
    # Then f3(bW[n-1], bW[n], bW[n+1]); returns [L(n), M(n), R(n)] where:
    with(numtheory);
    f3:=proc(a,b,c)
    local lefta,midb,rightc,i,p,pa,pc,ta,tb,tc,t1,t2;
    ta:=a; tb:=b; tc:=c;
    # left
    t1:=igcd(a,b);
    t2:=factorset(t1);
    t2:=convert(t2,list);
    lefta:=1;
    for i from 1 to nops(t2) do
    p:=t2[i];
    while (tb mod p) = 0 do lefta:=lefta*p; tb:=tb/p; od;
    od:
    # right
    t1:=igcd(b,c);
    t2:=factorset(t1);
    t2:=convert(t2,list);
    rightc:=1;
    for i from 1 to nops(t2) do
    p:=t2[i];
    while (tb mod p) = 0 do rightc:=rightc*p; tb:=tb/p; od;
    od:
    # middle
    midb:=b/(lefta*rightc);
    [lefta,midb,rightc];
    end; # N. J. A. Sloane, Mar 09 2023

A361129 Let b = A360519; let Lg = gcd(b(n-1),b(n)), Rg = gcd(b(n),b(n+1)); let L(n) = prod_{primes p|Lg} p-part of b(n), R(n) = prod_{primes p|Rg} p-part of b(n), M(n) = b(n)/(L(n)*R(n)); sequence gives M(n).

Original entry on oeis.org

3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 1, 1, 7, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 7, 1, 1, 1, 1, 1, 5, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 11, 1, 1, 11, 1, 1, 1, 1, 13, 1, 1, 1, 1, 1, 1, 9, 1, 1, 1, 1, 1, 1, 5, 17, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1
Offset: 2

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Comments

The p-part of a number k is the highest power of p that divides k. For example, the 2-part of 24 is 8, the 3-part is 3.
Since so many of the initial terms are 1, we show more than the usual number of terms in the DATA section.
Conjecture: All terms are odd, and every odd number eventually appears.

Crossrefs

A361130 Let b = A360519; let Lg = gcd(b(n-1),b(n)), Rg = gcd(b(n),b(n+1)); let L(n) = prod_{primes p|Lg} p-part of b(n), R(n) = prod_{primes p|Rg} p-part of b(n), M(n) = b(n)/(L(n)*R(n)); sequence gives R(n).

Original entry on oeis.org

2, 5, 7, 3, 4, 5, 11, 3, 2, 7, 11, 9, 5, 8, 11, 13, 3, 8, 7, 13, 5, 2, 17, 7, 9, 4, 13, 17, 3, 2, 19, 5, 9, 16, 11, 17, 5, 2, 23, 3, 19, 4, 13, 9, 25, 2, 29, 3, 31, 2, 7, 3, 37, 2, 17, 9, 41, 2, 5, 23, 7, 12, 5, 29, 7, 2, 27, 43, 5, 4, 3, 47, 5, 2, 9, 49, 19, 8, 3, 5, 31, 4, 43, 7
Offset: 2

Views

Author

Keywords

Comments

The p-part of a number k is the highest power of p that divides k. For example, the 2-part of 24 is 8, the 3-part is 3.

Crossrefs

Showing 1-10 of 36 results. Next