A362363 Arm number of the base spiral in A362249 which visits large spiral point n there.
0, 0, 2, 3, 0, 0, 0, 1, 0, 1, 2, 0, 2, 2, 0, 3, 0, 0, 0, 0, 0, 2, 0, 1, 0, 1, 0, 0, 2, 0, 2, 2, 2, 3, 0, 3, 0, 3, 0, 0, 0, 0, 0, 2, 0, 2, 0, 1, 0, 1, 0, 0, 2, 0, 2, 0, 2, 2, 2, 2, 0, 3, 0, 3, 0, 3, 0, 0, 0, 0, 0, 0, 0, 2, 0, 2, 0, 1, 0, 1, 0, 1, 0, 1, 2, 0, 2
Offset: 1
Keywords
Examples
a(5) = 0 because A362249(5) = 13 that is on spiral "E", which is encoded here as 0. a(8) = 1 because A362249(8) = 58 that is on spiral "S", which is encoded here as 1. a(11) = 2 because A362249(11) = 139 that is on spiral "W", which is encoded here as 2. a(34) = 3 because A362249(34) = 1000 that is on spiral "N", which is encoded here as 3.
Programs
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MATLAB
function a = A362363( max_n ) E = [0 ; 0]; S = [0 ; 0]; W = [0 ; 0]; N = [0 ; 0]; V = [0 0]; for k = 1:4*max_n l = V(1+mod(k+1,2)); s = (-1)^floor(k/2); for m = l+(1*s):s:s*k V(1+mod(k+1,2)) = m; V2 = V(end:-1:1).*[-1 1]; N = [N V2']; E = [E V']; S = [S -V2']; W = [W -V']; end end for n = 2:max_n [th,r] = cart2pol(E(1,n), E(2,n)); rot = [cos(-th) -sin(-th); sin(-th) cos(-th)]; v = E(:,n)'*rot*r; jE = find(sum(abs([E(1,:)-v(1); E(2,:)-v(2)]),1) < 0.5); jS = find(sum(abs([S(1,:)-v(1); S(2,:)-v(2)]),1) < 0.5); jW = find(sum(abs([W(1,:)-v(1); W(2,:)-v(2)]),1) < 0.5); jN = find(sum(abs([N(1,:)-v(1); N(2,:)-v(2)]),1) < 0.5); a(n-1) = find([length(jE) length(jS) length(jW) length(jN)] > 0) - 1; end end % Thomas Scheuerle, Apr 19 2023
Formula
If n is a square:
a(n) = 3*(n+1 mod 2); (a(n) = 3 for even squares).
Comments