cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A364255 a(n) = gcd(n, A163511(n)).

Original entry on oeis.org

1, 1, 2, 3, 4, 1, 6, 1, 8, 9, 2, 1, 12, 1, 2, 1, 16, 1, 18, 1, 4, 3, 2, 1, 24, 5, 2, 1, 4, 1, 2, 1, 32, 3, 2, 5, 36, 1, 2, 1, 8, 1, 6, 1, 4, 3, 2, 1, 48, 1, 10, 1, 4, 1, 2, 11, 8, 3, 2, 1, 4, 1, 2, 1, 64, 1, 6, 1, 4, 3, 10, 1, 72, 1, 2, 5, 4, 7, 2, 1, 16, 27, 2, 1, 12, 5, 2, 1, 8, 1, 6, 1, 4, 3, 2, 1, 96, 1, 2, 1, 20, 1, 2, 1, 8, 105
Offset: 0

Views

Author

Antti Karttunen, Jul 16 2023

Keywords

Crossrefs

Cf. A163511, A364257 (Dirichlet inverse), A364258, A364491, A364492, A364493.

Programs

  • PARI
    A163511(n) = if(!n,1,my(p=2, t=1); while(n>1, if(!(n%2), (t*=p), p=nextprime(1+p)); n >>= 1); (t*p));
    A364255(n) = gcd(n, A163511(n)); \\ Antti Karttunen, Sep 01 2023
  • Python
    from math import gcd
    from sympy import nextprime
    def A364255(n):
        c, p, k = 1, 1, n
        while k:
            c *= (p:=nextprime(p))**(s:=(~k&k-1).bit_length())
            k >>= s+1
        return gcd(c*p,n) # Chai Wah Wu, Jul 25 2023
    

Formula

From Antti Karttunen, Sep 01 2023: (Start)
a(n) = gcd(n, A364258(n)) = gcd(A163511(n), A364258(n)).
a(n) = n / A364491(n) = A163511(n)/ A364492(n).
(End)

A364492 a(n) = A163511(n) / gcd(n, A163511(n)).

Original entry on oeis.org

1, 2, 2, 1, 2, 9, 1, 5, 2, 3, 9, 25, 1, 15, 5, 7, 2, 81, 3, 125, 9, 25, 25, 49, 1, 9, 15, 35, 5, 21, 7, 11, 2, 81, 81, 125, 3, 375, 125, 343, 9, 225, 25, 245, 25, 49, 49, 121, 1, 135, 9, 175, 15, 105, 35, 7, 5, 21, 21, 55, 7, 33, 11, 13, 2, 729, 81, 3125, 81, 625, 125, 2401, 3, 1125, 375, 343, 125, 147, 343, 1331
Offset: 0

Views

Author

Antti Karttunen, Jul 26 2023

Keywords

Comments

Denominator of n / A163511(n).

Crossrefs

Cf. A163511, A364255, A364491 (numerators), A364493, A364496 (positions of 1's).

Programs

  • PARI
    A005940(n) = { my(p=2, t=1); n--; until(!n\=2, if((n%2), (t*=p), p=nextprime(p+1))); t };
    A054429(n) = ((3<<#binary(n\2))-n-1);
    A163511(n) = if(!n,1,A005940(1+A054429(n)))
    A364492(n) = { my(u=A163511(n)); (u/gcd(n, u)); };
    
  • Python
    from math import gcd
    from sympy import nextprime
    def A364492(n):
        c, p, k = 1, 1, n
        while k:
            c *= (p:=nextprime(p))**(s:=(~k&k-1).bit_length())
            k >>= s+1
        return c*p//gcd(c*p,n) # Chai Wah Wu, Jul 26 2023

Formula

a(n) = A163511(n) / A364255(n) = A163511(n) / gcd(n, A163511(n)).

A364491 a(n) = n / gcd(n, A163511(n)).

Original entry on oeis.org

0, 1, 1, 1, 1, 5, 1, 7, 1, 1, 5, 11, 1, 13, 7, 15, 1, 17, 1, 19, 5, 7, 11, 23, 1, 5, 13, 27, 7, 29, 15, 31, 1, 11, 17, 7, 1, 37, 19, 39, 5, 41, 7, 43, 11, 15, 23, 47, 1, 49, 5, 51, 13, 53, 27, 5, 7, 19, 29, 59, 15, 61, 31, 63, 1, 65, 11, 67, 17, 23, 7, 71, 1, 73, 37, 15, 19, 11, 39, 79, 5, 3, 41, 83, 7, 17, 43, 87
Offset: 0

Views

Author

Antti Karttunen, Jul 26 2023

Keywords

Comments

Numerator of n / A163511(n).

Crossrefs

Cf. A163511, A364255, A364492 (denominators), A364493, A364494 (positions of 1's).

Programs

  • PARI
    A005940(n) = { my(p=2, t=1); n--; until(!n\=2, if((n%2), (t*=p), p=nextprime(p+1))); t };
    A054429(n) = ((3<<#binary(n\2))-n-1); \\ From A054429
    A163511(n) = if(!n,1,A005940(1+A054429(n)))
    A364491(n) = (n/gcd(n, A163511(n)));
    
  • Python
    from math import gcd
    from sympy import nextprime
    def A364491(n):
        c, p, k = 1, 1, n
        while k:
            c *= (p:=nextprime(p))**(s:=(~k&k-1).bit_length())
            k >>= s+1
        return n//gcd(c*p,n) # Chai Wah Wu, Jul 26 2023

Formula

a(n) = n / A364255(n) = n / gcd(n, A163511(n)).
Showing 1-3 of 3 results.