cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A370365 Total sum over all j in [n] of the number of partitions of [j*(n-j)] into (n-j) sets of size j having at least one set of consecutive numbers whose maximum (if j>0) is a multiple of j.

Original entry on oeis.org

0, 1, 2, 3, 4, 11, 77, 1571, 101924, 21824842, 18998281193, 63437859518312, 1037654210033812290, 72422876152852051595343, 27306605231809196751929593081, 50723306700937648229840111395656830, 510196838745355443955126736574361550469276
Offset: 0

Views

Author

Alois P. Heinz, Feb 16 2024

Keywords

Crossrefs

Antidiagonal sums of A370363.

Programs

  • Maple
    b:= proc(n, k) option remember; `if`(k=0, signum(n), add(
          (-1)^(n-j+1)*binomial(n, j)*(k*j)!/(j!*k!^j), j=0..n-1))
        end:
    a:= n-> add(b(j, n-j), j=0..n):
    seq(a(n), n=0..16);

Formula

a(n) = Sum_{j=0..n} A370363(j,n-j).
a(n) = A370407(n) - A370368(n).

A370368 Total sum over all j in [n] of the number of partitions of [j*(n-j)] into (n-j) sets of size j having no set of consecutive numbers whose maximum (if j>0) is a multiple of j.

Original entry on oeis.org

1, 1, 1, 1, 3, 18, 347, 20679, 4064088, 3206794270, 9817417580226, 147957639234186793, 9515125170594095021483, 3369265619091187775505912588, 5792039079391869138256364232105952, 55416702792637442337898498177490975722265
Offset: 0

Views

Author

Alois P. Heinz, Feb 16 2024

Keywords

Crossrefs

Antidiagonal sums of A370366.

Programs

  • Maple
    b:= proc(n, k) `if`(k=0, `if`(n=0, 1, 0), add(
          (-1)^(n-j)*binomial(n, j)*(k*j)!/(j!*k!^j), j=0..n))
        end:
    a:= n-> add(b(j, n-j), j=0..n):
    seq(a(n), n=0..15);

Formula

a(n) = Sum_{j=0..n} A370366(j,n-j).
a(n) = A370407(n) - A370365(n).

A361948 Array read by ascending antidiagonals. A(n, k) = Product_{j=0..k-1} binomial((j + 1)*n - 1, n - 1) if n >= 1, and A(0, k) = 1 for all k.

Original entry on oeis.org

1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 10, 15, 1, 1, 1, 1, 35, 280, 105, 1, 1, 1, 1, 126, 5775, 15400, 945, 1, 1, 1, 1, 462, 126126, 2627625, 1401400, 10395, 1, 1, 1, 1, 1716, 2858856, 488864376, 2546168625, 190590400, 135135, 1, 1
Offset: 0

Views

Author

Peter Luschny, Apr 13 2023

Keywords

Comments

Row n gives the leading coefficients of the set partition polynomials of type n. The sequence of these polynomial sequences starts: A097805, A048993, A156289, A291451, A291452, ...

Examples

			Array A(n, k) starts:
  [0] 1, 1,   1,       1,           1,                 1, ...
  [1] 1, 1,   1,       1,           1,                 1, ...
  [2] 1, 1,   3,      15,         105,               945, ...  A001147
  [3] 1, 1,  10,     280,       15400,           1401400, ...  A025035
  [4] 1, 1,  35,    5775,     2627625,        2546168625, ...  A025036
  [5] 1, 1, 126,  126126,   488864376,     5194672859376, ...  A025037
  [6] 1, 1, 462, 2858856, 96197645544, 11423951396577720, ...  A025038
.
Triangle A(n-k, k) starts:
  [0] 1;
  [1] 1, 1;
  [2] 1, 1,  1;
  [3] 1, 1,  1,   1;
  [4] 1, 1,  3,   1,   1;
  [5] 1, 1, 10,  15,   1, 1;
  [6] 1, 1, 35, 280, 105, 1, 1;
		

Crossrefs

Cf. A060540 (subarray), A370407 (antidiagonal sums, row sums).
Cf. A001147 (row 2), A025035 (row 3), A025036 (row 4), A025037 (row 5), A025038 (row 6), A025039 (row 7), A025040 (row 8), A025041 (row 9).
Cf. A088218 (column 2), A060542 (column 3), A082368 (column 4), A322252 (column 5), A057599 (main diagonal).

Programs

  • Maple
    A := (n, k) -> mul(binomial((j + 1)*n - 1, n - 1), j = 0..k-1):
    seq(seq(A(n-k, k), k = 0..n), n = 0..9);
    # Alternative, using recursion:
    A := proc(n, k) local P; P := proc(n, k) option remember;
    if n = 0 then return x^k*k! fi; if k = 0 then 1 else add(binomial(n*k, n*j)*
    P(n,k-j)*x, j=1..k) fi end: coeff(P(n, k), x, k) / k! end:
    seq(print(seq(A(n, k), k = 0..5)), n = 0..6);
    # Alternative, using exponential generating function:
    egf := n -> ifelse(n=0, 1, exp(x^n/n!)): ser := n -> series(egf(n), x, 8*n):
    row := n -> local k; seq((n*k)!*coeff(ser(n), x, n*k), k = 0..6):
    for n from 0 to 6 do [n], row(n) od;  # Peter Luschny, Aug 15 2024
  • Mathematica
    A[n_, k_] := Product[Binomial[n (j + 1) - 1, n - 1], {j, 0, k - 1}]; Table[A[n - k, k], {n, 0, 9}, {k, 0, n}] // Flatten (* Michael De Vlieger, Apr 13 2023 *)
  • SageMath
    def Arow(n, size):
        if n == 0: return [1] * size
        return [prod(binomial((j + 1)*n - 1, n - 1) for j in range(k)) for k in range(size)]
    for n in range(7): print(Arow(n, 7))
    # Alternative, using exponential generating function:
    def SetPolyLeadCoeff(m, n):
        x, z = var("x, z")
        if m == 0: return 1
        w = exp(2 * pi * I / m)
        o = sum(exp(z * w ** k) for k in range(m)) / m
        t = exp(x * (o - 1)).taylor(z, 0, m*n)
        p = factorial(m*n) * t.coefficient(z, m*n)
        return p.leading_coefficient(x)
    for m in range(7):
        print([SetPolyLeadCoeff(m, k) for k in range(6)])

Formula

A(n, k) = (1/k!) * [x^k] P(n, k), where P(n, k) = k!*x^k if n = 0 and otherwise 1 if k = 0 and otherwise Sum_{j=1..k} binomial(n*k, n*j)*P(n, k-j)*x.
A(n, k) = (n*k)!*[x^(n*k)] exp(x^n/n!) for n >= 1. - Peter Luschny, Aug 15 2024
Showing 1-3 of 3 results.