cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A369859 Minimum chord of a chordal ring graph with 2*n vertices and minimal diameter.

Original entry on oeis.org

1, 1, 3, 3, 3, 5, 5, 5, 5, 5, 5, 5, 5, 7, 7, 7, 7, 7, 15, 7, 7, 9, 7, 19, 7, 9, 9, 9, 9, 9, 9, 11, 19, 19, 9, 9, 21, 11, 29, 23, 23, 11, 11, 25, 11, 11, 11, 11, 11, 13, 13, 23, 23, 41, 11, 25, 25, 13, 15, 27, 27, 27, 13, 13, 29, 29, 13, 13, 13, 31, 13, 15, 15, 15, 17, 27, 13, 43, 29, 29, 29, 45, 17, 17, 31, 31, 31, 39
Offset: 1

Views

Author

Miquel A. Fiol, Apr 30 2024

Keywords

Comments

Given integers n and c (odd), the chordal ring graph CR(2*n,c) is a bipartite graph with vertex set Z_{2*n}, and edges {i,i+1}, {i,i-1}, {i,i+c} if i is odd, and {i,i-c} if i is even.

Crossrefs

Cf. A371396.

A373503 The minimum diameter of a chordal ring graph with 2*n vertices.

Original entry on oeis.org

1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 5, 6, 6, 6, 7, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 7, 8, 8, 8, 8, 9, 9, 8, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 10, 9, 9, 10, 10, 10, 9, 10, 11, 11, 10, 10, 11, 11, 11, 10, 11, 11, 11, 11, 11, 11, 12, 11, 11, 11, 11, 11, 12, 12, 11, 11, 12, 12
Offset: 1

Views

Author

Miquel A. Fiol, Jul 10 2024

Keywords

Crossrefs

A374622 Maximum number of vertices of a chordal ring mixed graph CRM(N,c) with diameter n.

Original entry on oeis.org

8, 10, 18, 16, 32, 34, 50, 44, 72, 74, 98, 88, 128, 130, 162, 148, 200, 202, 242, 224, 288, 290, 338, 316, 392, 394, 450, 424, 512, 514, 578, 548, 648, 650, 722, 688, 800, 802, 882, 844, 968, 970, 1058, 1016, 1152, 1154
Offset: 3

Views

Author

Miquel A. Fiol, Jul 14 2024

Keywords

Examples

			For n = 9, the maximum number of vertices a(9) = 50 is attained by the chordal ring mixed graph CRM(50,9).
		

Crossrefs

Cf. A371396.

Formula

If n is odd, a(n) = (n+1)^2/2.
Conjecture: If n is even, n=0 mod 4, a(n) = n^2/2+2;
If n (> 2) is even, n=2 mod 4, a(n) = n*(n/2 - 1) + 4.
Conjectured g.f.: 2*(1 + x + 2*x^2 + x^3 + 2*x^4 - 3*x^5 + 4*x^6 - x^7 + x^8)/((1 - x)^3*(1 + x + x^2 + x^3)^2). - Stefano Spezia, Jul 14 2024
Showing 1-3 of 3 results.