A374358 -id:A374358 - cp's OEIS frontend

A374359 a(1) = 2, a(n) = 5 for n > 1.

2, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5

Offset: 1

Stefano Spezia, Jul 06 2024

Decimal expansion of 23/9, which is an approximation of the 5th root of 109 (A374357).

Simple continued fraction expansion of (1 + sqrt(29))/14 = (1 + A010484)/14.

			2.555555555555555555555555555555555555555...

Greg Martin and Winnie Miao, abc triples, arXiv:1409.2974 [math.NT], 2014. See p. 5.
Index entries for linear recurrences with constant coefficients, signature (1).

Cf. A374357 (decimal expansion of the 5th root of 109), A374358 (continued fraction of the 5th root of 109).
Cf. A010484.
Essentially the same as A021022 and A010716.

Mathematica
```
LinearRecurrence[{1},{2,5},100]
```

G.f.: x*(2 + 3*x)/(1 - x).
a(n) = a(n-1) for n > 2.
E.g.f.: 5*exp(x) - 3*x - 5.

A374357 Decimal expansion of the 5th root of 109.

Original entry on oeis.org

2, 5, 5, 5, 5, 5, 5, 3, 9, 6, 7, 3, 5, 1, 8, 9, 8, 1, 7, 0, 4, 1, 8, 2, 0, 4, 7, 1, 2, 8, 0, 0, 9, 4, 0, 4, 5, 2, 1, 2, 8, 1, 4, 3, 0, 5, 1, 3, 3, 2, 5, 5, 8, 1, 5, 9, 6, 8, 3, 6, 2, 4, 9, 0, 2, 4, 5, 5, 0, 2, 8, 7, 5, 6, 5, 3, 8, 3, 2, 1, 8, 1, 1, 1, 6, 3, 5, 2, 1, 6, 5, 0, 1, 7, 6, 3, 8, 1, 0, 0

Offset: 1

Stefano Spezia, Jul 06 2024

			2.555555396735189817041820471280094045212814305...

Greg Martin and Winnie Miao, abc triples, arXiv:1409.2974 [math.NT], 2014. See p. 5.
Index entries for sequences related to the decimal expansion of the n-th root of x.

Cf. A374358 (continued fraction), A374359 (decimal expansion of the third convergent).

Mathematica
```
RealDigits[109^(1/5),10,100][[1]]
```

from sympy import integer_nthroot
def A374357(n): return integer_nthroot(109*10**(5*(n-1)),5)[0]%10 # Chai Wah Wu, Jul 07 2024

cp's OEIS Frontend

A374359 a(1) = 2, a(n) = 5 for n > 1.

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