A376056 Lexicographically earliest sequence of positive integers a(1), a(2), a(3), ... such that for any n > 0, S(n) = Sum_{k = 1..n} (2*k-1)/a(k) < 1.
2, 7, 71, 6959, 62255215, 4736981006316791, 26518805245879857416837904442871, 811438882694890436523185183518581584358651922339197834228784351
Offset: 1
Crossrefs
Programs
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Maple
# Given a sequence b(1), b(2), b(3), ... of nonnegative real numbers, this program computes the first M terms of the lexicographically earliest sequence of positive integers a(1), a(2), a(3), ... with the property that for any n > 0, S(n) = Sum_{k = 1..n} b(k)/a(k) < 1. # For the present sequence we set b(k) = 2*k - 1. b := Array(0..100,-1); a := Array(0..100,-1); S := Array(0..100,-1); d := Array(0..100,-1); for k from 1 to 100 do b[k]:=2*k-1; od: M:=8; S[0] := 0; d[0] := 1; for n from 1 to M do a[n] := floor(b[n]/d[n-1])+1; S[n] := S[n-1] + b[n]/a[n]; d[n] := 1 - S[n]; od: La:=[seq(a[n],n=1..M)]; # the present sequence Ls:=[seq(S[n],n=1..M)]; # the sums S(n) Lsn:=[seq(numer(S[n]),n=1..M)]; Lsd:=[seq(denom(S[n]),n=1..M)]; # A376057 Lsd-Lsn; # As a check, by the above theorem, this should (and does) produce the all-1's sequence # Some small changes to the program are needed if the starting sequence {b(n)} has offset 0, as for example in the case of the Fibonacci or Catalan numbers (see A376058-A376061).
Formula
a(n+1) = (2*n+1)*A376057(n) + 1.
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