A379547 Expansion of (1/x) * Series_Reversion( x / ( (1+x)^2 * (1+2*x)^4 ) ).
1, 10, 141, 2318, 41586, 789404, 15588677, 316957910, 6591000606, 139521610540, 2996554128002, 65135251885164, 1430214488595340, 31676376789702720, 706819317765805461, 15874751837921964646, 358585244386746378166, 8141109472248910295708
Offset: 0
Programs
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Mathematica
CoefficientList[InverseSeries[Series[x / ( (1+x)^2 * (1+2*x)^4 ),{x,0,18}],x]/x,x] (* Stefano Spezia, Aug 25 2025 *)
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PARI
my(N=20, x='x+O('x^N)); Vec(serreverse(x/((1+x)^2*(1+2*x)^4))/x)
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PARI
a(n) = sum(k=0, n\2, 2^(n-2*k)*binomial(n+1, k)*binomial(5*(n+1)-k, n-2*k))/(n+1);
Formula
a(n) = (1/(n+1)) * Sum_{k=0..n} 2^k * binomial(4*(n+1),k) * binomial(2*(n+1),n-k).
a(n) = (1/(n+1)) * Sum_{k=0..floor(n/2)} 2^(n-2*k) * binomial(n+1,k) * binomial(5*(n+1)-k,n-2*k).
a(n) = (1/(n+1)) * [x^n] ( (1+x)^2 * (1+2*x)^4 )^(n+1).