cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A365638 Triangular array read by rows: T(n, k) is the number of ways that a k-element transitive tournament can occur as a subtournament of a larger tournament on n labeled vertices.

Original entry on oeis.org

1, 1, 1, 2, 4, 2, 8, 24, 24, 6, 64, 256, 384, 192, 24, 1024, 5120, 10240, 7680, 1920, 120, 32768, 196608, 491520, 491520, 184320, 23040, 720, 2097152, 14680064, 44040192, 55050240, 27525120, 5160960, 322560, 5040, 268435456, 2147483648, 7516192768, 11274289152, 7046430720, 1761607680, 165150720, 5160960, 40320
Offset: 0

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Author

Thomas Scheuerle, Sep 14 2023

Keywords

Comments

A tournament is a directed digraph obtained by assigning a direction for each edge in an undirected complete graph. In a transitive tournament all nodes can be strictly ordered by their reachability.

Examples

			Triangle begins:
     1
     1,     1
     2,     4,     2
     8,    24,    24,     6
    64,   256,   384,   192,    24
  1024,  5120, 10240,  7680,  1920,  120
		

Crossrefs

Programs

  • Maple
    T := (n, k) -> 2^(((n-1)*n - (k-1)*k)/2) * n! / (n-k)!:
    seq(seq(T(n, k), k = 0..n), n = 0..8);  # Peter Luschny, Nov 02 2023
  • PARI
    T(n, k) = binomial(n, k)*k!*2^(binomial(n, 2) - binomial(k, 2))

Formula

T(n, k) = binomial(n, k)*k!*2^(binomial(n, 2) - binomial(k, 2)).
T(n, 0) = A006125(n).
T(n, 1) = A095340(n).
T(n, 2) = A103904(n).
T(n, n) = n!.
T(n, n-1) = A002866(n-1).
T(n, n-2) = A052670(n).
T(n, k) = A008279(n, k) * A117260(n, k). - Peter Luschny, Dec 31 2024

A382240 a(n) = Sum_{k=0..n} 3^((n+k-1)*(n-k)/2) * n! / (n-k)!.

Original entry on oeis.org

1, 2, 11, 168, 7233, 889014, 314965899, 323989244676, 972969439627809, 8566667168429128842, 221877626825222187484203, 16949442370817602102051560384, 3827091229259231090623800852526113, 2558686452439976557585601153755243553406, 5072634396431144733070212976874036427346208619
Offset: 0

Views

Author

Vaclav Kotesovec, Mar 19 2025

Keywords

Comments

In general, for m>1, Sum_{k=0..n} m^((n+k-1)*(n-k)/2) * n! / (n-k)! ~ sqrt(2*Pi/log(m)) * n^(log(n)/(2*log(m)) + 1/2) * m^((2*n - 1)^2/8).

Crossrefs

Cf. A379614.

Programs

  • Mathematica
    Table[Sum[3^((n+k-1)*(n-k)/2) * n!/(n-k)!, {k, 0, n}], {n, 0, 15}]

Formula

a(n) ~ sqrt(2*Pi/log(3)) * n^(log(n)/(2*log(3)) + 1/2) * 3^((2*n-1)^2/8).
Showing 1-2 of 2 results.