A384311 a(n) is the number of ways to partition an n X n X n cube into 4 noncongruent cuboids.
0, 0, 4, 12, 47, 85, 183, 266, 466, 613, 941, 1179, 1668, 2007, 2701, 3159, 4079, 4690, 5868, 6635, 8122, 9064, 10874, 12030, 14196, 15564, 18142, 19740, 22739, 24613, 28065, 30206, 34174, 36601, 41087, 43851, 48888, 51975, 57631, 61059, 67331, 71158, 78078
Offset: 1
Examples
The triplets (1,1,1) and (2,2,2) cannot be decomposed into 4 distinct triplets giving first two terms a(1) = a(2) = 0. According to the rule there is only one way to decompose the triplet (3,3,3) into two distinct triplets, those are (3,3,1) and (3,3,2) and by applying the rule to each of the triplets at a time gives two sets of triplets {(3,3,2), (3,2,1), (3,1,1)} and {(3,3,1), (3,2,2), (3,1,1)}. Finally by repeating the process for each of the triplets of the stage three at a time gives the following sets of four distinct triplets: {(3,3,2), (3,2,1), (2,1,1), (1,1,1)}; {(3,3,2), (3,1,1), (2,2,1), (2,1,1)}; {(3,3,1), (3,2,2), (2,2,1), (2,1,1)}; {(3,3,1), (3,2,1), (2,2,2), (2,2,1)}. Therefore, a(3)=4.
Links
- Sean A. Irvine, Table of n, a(n) for n = 1..200
- Index entries for linear recurrences with constant coefficients, signature (-1,1,3,3,-1,-4,-4,-1,3,3,1,-1,-1).
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