cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A285739 Numerator of discriminant of n-th Bernoulli polynomial.

Original entry on oeis.org

1, 1, 1, 28, 343, 31, 29791, 178035712, 11651995228221, 1087618835548371875, 13429024118357421875, 143533445691269324970571729935778225264543312, 91376242719004834465589805254054451484345405903423332764620213, 25397841834482816377486479267527401525220329290217
Offset: 1

Views

Author

Ilya Gutkovskiy, Apr 25 2017

Keywords

Examples

			1, 1/3, 1/16, 28/3375, 343/559872, 31/1815156, 29791/80621568, 178035712/124556484375, 11651995228221/80000000000000, ...
The first few Bernoulli polynomials are
0 | 1;
1 | x - 1/2;
2 | x^2 - x + 1/6;
3 | x^3 - 3*x^2/2 + x/2;
4 | x^4 - 2*x^3 + x^2 - 1/30;
5 | x^5 - 5*x^4/2 + 5*x^3/3 - x/6, etc.
		

Crossrefs

Cf. A053382, A053383, A196838, A196839, A285740 (denominators).

Programs

  • Mathematica
    Table[Numerator[Discriminant[BernoulliB[n, x], x]], {n, 1, 14}]
  • PARI
    a(n) = numerator(poldisc(bernpol(n))); \\ Michel Marcus, Mar 02 2023

A285740 Denominator of discriminant of n-th Bernoulli polynomial.

Original entry on oeis.org

1, 3, 16, 3375, 559872, 1815156, 80621568, 124556484375, 80000000000000, 11881340006899968, 1218719480020992, 3405780508865246682482292626953125, 1526226812966134209666905971200000000000000000, 18160335421875000000000000
Offset: 1

Views

Author

Ilya Gutkovskiy, Apr 25 2017

Keywords

Examples

			1, 1/3, 1/16, 28/3375, 343/559872, 31/1815156, 29791/80621568, 178035712/124556484375, 11651995228221/80000000000000, ...
The first few Bernoulli polynomials are
0 | 1;
1 | x - 1/2;
2 | x^2 - x + 1/6;
3 | x^3 - 3*x^2/2 + x/2;
4 | x^4 - 2*x^3 + x^2 - 1/30;
5 | x^5 - 5*x^4/2 + 5*x^3/3 - x/6, etc.
		

Crossrefs

Cf. A053382, A053383, A196838, A196839, A285739 (numerators).

Programs

  • Mathematica
    Table[Denominator[Discriminant[BernoulliB[n, x], x]], {n, 1, 14}]
  • PARI
    a(n) = denominator(poldisc(bernpol(n))); \\ Michel Marcus, Mar 02 2023

A333303 T(n, k) = [x^k] (-2)^n*(B(n, x/2) - B(n, (x+1)/2)) where B(n, x) are the Bernoulli polynomials. Triangle read by rows, for 0 <= k <= n.

Original entry on oeis.org

0, 1, 1, -2, 0, -3, 3, -1, 0, 6, -4, 0, 5, 0, -10, 5, 3, 0, -15, 0, 15, -6, 0, -21, 0, 35, 0, -21, 7, -17, 0, 84, 0, -70, 0, 28, -8, 0, 153, 0, -252, 0, 126, 0, -36, 9, 155, 0, -765, 0, 630, 0, -210, 0, 45, -10, 0, -1705, 0, 2805, 0, -1386, 0, 330, 0, -55, 11
Offset: 0

Views

Author

Peter Luschny, May 07 2020

Keywords

Comments

Can be seen as the Bernoulli counterpart of the Euler triangles A247453 and A109449.

Examples

			B*(8, z) = 1024*(Zeta(-7, (z+1)/2) - Zeta(-7, z/2))
         = -17 + 84*z^2 - 70*z^4 + 28*z^6 - 8*z^7.
Triangle starts:
[ 0] [  0]
[ 1] [  1]
[ 2] [  1,    -2]
[ 3] [  0,    -3,    3]
[ 4] [ -1,     0,    6,   -4]
[ 5] [  0,     5,    0,  -10,   5]
[ 6] [  3,     0,  -15,    0,  15,    -6]
[ 7] [  0,   -21,    0,   35,   0,   -21,    7]
[ 8] [-17,     0,   84,    0, -70,     0,   28,  -8]
[ 9] [  0,   153,    0, -252,   0,   126,    0, -36,  9]
[10] [155,     0, -765,    0, 630,     0, -210,   0, 45, -10]
[11] [  0, -1705,    0, 2805,   0, -1386,    0, 330,  0, -55, 11]
		

Crossrefs

Row sums are (-1)^n*A226158(n). Alternating row sums are A239977(n).
Cf. A181983, A247453, A109449, (A053382/A053383) Bernoulli polynomials.

Programs

  • Mathematica
    B[n_, x_] := (-2)^n (BernoulliB[n, x/2] - BernoulliB[n, (x + 1)/2]);
    Prepend[Table[CoefficientList[B[n, x], x], {n, 1, 11}], 0] // Flatten
  • SageMath
    def Bstar(n,x):
        return (-2)^n*(bernoulli_polynomial(x/2,n) - bernoulli_polynomial((x+1)/2,n))
    print(flatten([expand(Bstar(n, x)).list() for n in (0..11)]))

Formula

Let B*(n, x) denote the alternating Bernoulli rational polynomial functions defined by Z*(s, x) = Phi(-1, s, x) and B*(s, x) = -s Z*(1 - s, x). Here Phi(z, s, x) is the Hurwitz-Lerch transcendent defined as an analytic continuation of Sum_{k>=0} z^k/(k+x)^s. Then T(n, k) = (-1)^n [x^k] 2 B*(n, x).
T(n, 0) = 2*(2^n - 1)*Bernoulli(n, 1) = n*Euler(n - 1, 1) = -A226158(n).
Main diagonal is (-1)^(n+1)*n = A181983(n).
Previous Showing 21-23 of 23 results.