A061520
a(0) = 0; a(n) is obtained by incrementing each digit of a(n-1) by 6.
Original entry on oeis.org
0, 6, 12, 78, 1314, 79710, 13151376, 79711791312, 1315137713157978, 797117913137971113151314, 1315137713157979131513777971179710, 797117913137971113151315797117913131315137713151376
Offset: 0
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g:= proc(n) op(convert(n+6,base,10)) end proc:
L[0]:= [0]:
for n from 1 to 12 do L[n]:= map(g,L[n-1]) od:
map(t -> add(t[i]*10^(i-1),i=1..nops(t)), [seq(L[i],i=0..12)]): # Robert Israel, Jan 26 2020
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Nest[Append[#, FromDigits@ Flatten@ IntegerDigits[IntegerDigits@ #[[-1]] + 6]] &, {0}, 11] (* Michael De Vlieger, Jan 26 2020 *)
NestList[FromDigits[Flatten[IntegerDigits/@(IntegerDigits[#]+6)]]&,0,15] (* Harvey P. Dale, Jan 10 2021 *)
More terms from Larry Reeves (larryr(AT)acm.org), May 11 2001
A061514
a(0) = 0; a(n) is obtained by incrementing each digit of a(n-1) by 3.
Original entry on oeis.org
0, 3, 6, 9, 12, 45, 78, 1011, 4344, 7677, 1091010, 43124343, 76457676, 10978109109, 4312101143124312, 7645434476457645, 1097876771097810978, 4312101110910104312101143121011, 76454344431243437645434476454344
Offset: 0
More terms from Larry Reeves (larryr(AT)acm.org), May 11 2001
A061515
a(0) = 1; a(n) is obtained by incrementing each digit of a(n-1) by 3.
Original entry on oeis.org
1, 4, 7, 10, 43, 76, 109, 4312, 7645, 10978, 43121011, 76454344, 109787677, 431210111091010, 7645434443124343, 10978767776457676, 43121011109101010978109109, 76454344431243434312101143124312, 109787677764576767645434476457645, 431210111091010109781091091097876771097810978
Offset: 0
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from itertools import accumulate, repeat
def f(n, _): return int("".join(str(int(d)+3) for d in str(n)))
def aupton(nn): return list(accumulate(repeat(1, nn+1), f))
print(aupton(19)) # Michael S. Branicky, Mar 19 2022
More terms from Larry Reeves (larryr(AT)acm.org), May 11 2001
A061516
a(0) = 1; a(n) is obtained by incrementing each digit of a(n-1) by 4.
Original entry on oeis.org
1, 5, 9, 13, 57, 911, 1355, 5799, 9111313, 13555757, 5799911911, 911131313551355, 1355575757995799, 579991191191113139111313, 9111313135513551355575713555757, 135557575799579957999119115799911911
Offset: 0
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a[0]=1;a[n_]:=a[n]=FromDigits[Flatten[IntegerDigits/@(IntegerDigits[a[n-1]]+4)]]; Table[a[n],{n,0,15}] (* Zak Seidov, Mar 09 2006 *)
More terms from Larry Reeves (larryr(AT)acm.org), May 11 2001
A061518
a(0) = 0; a(n) is obtained by incrementing each digit of a(n-1) by 5.
Original entry on oeis.org
0, 5, 10, 65, 1110, 6665, 11111110, 66666665, 1111111111111110, 6666666666666665, 11111111111111111111111111111110, 66666666666666666666666666666665, 1111111111111111111111111111111111111111111111111111111111111110
Offset: 0
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from itertools import accumulate, repeat
def f(n, _): return int("".join(str(int(d)+5) for d in str(n)))
def aupton(nn): return list(accumulate(repeat(0, nn+1), f))
print(aupton(12)) # Michael S. Branicky, Mar 19 2022
More terms from Larry Reeves (larryr(AT)acm.org), May 11 2001
a(3) and following corrected and formula removed by
Georg Fischer, Mar 19 2022
A061521
a(0) = 1; a(n) is obtained by incrementing each digit of a(n-1) by 6.
Original entry on oeis.org
1, 7, 13, 79, 1315, 79711, 13151377, 79711791313, 1315137713157979, 797117913137971113151315, 1315137713157979131513777971179711, 797117913137971113151315797117913131315137713151377, 131513771315797913151377797117971113151377131579797971179131379711791313
Offset: 0
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NestList[FromDigits[Flatten[IntegerDigits/@(IntegerDigits[#]+6)]]&,1,15] (* Harvey P. Dale, May 21 2015 *)
More terms from Larry Reeves (larryr(AT)acm.org), May 11 2001
A061748
a(0) = 1; a(n) is obtained by incrementing each digit of a(n-1) by 8.
Original entry on oeis.org
1, 9, 17, 915, 17913, 91517911, 179139151799, 91517911179139151717, 1791391517999151791117913915915, 91517911179139151717179139151799915179111791317913
Offset: 0
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NestList[FromDigits[Flatten[IntegerDigits/@(IntegerDigits[#]+8)]]&,1,10] (* Harvey P. Dale, Aug 20 2012 *)
More terms from Larry Reeves (larryr(AT)acm.org), May 11 2001
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