cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Previous Showing 11-12 of 12 results.

A073772 Number of highly composite numbers (HCNs) between the n-th highly composite number k and 2*k if 2*k is a highly composite number, or -1 if 2*k is not a highly composite number.

Original entry on oeis.org

0, 0, -1, 0, 0, 1, -1, -1, 0, 1, 1, -1, 0, -1, 1, 1, -1, 0, 1, 1, 1, -1, -1, 2, 2, -1, -1, 1, 1, 1, 2, -1, 2, 2, -1, -1, -1, 1, 1, 1, 2, -1, 2, 2, -1, 2, 2, 2, -1, -1, 2, -1, 2, -1, 2, 2, -1, 2, 2, 2, -1, -1, 2, 2, 2, -1, 2, 3, -1, -1, 2, 2, 2, -1, -1, 1, 1, 1, 1, -1, -1, 3, 3, 3, 3, -1, -1, 2, 2, 2, -1, 1, 1, -1, 3, 3, 3, 3
Offset: 1

Views

Author

Klaus Brockhaus, Aug 19 2002

Keywords

Comments

If 2*A002182(n) = A002182(m) then a(n) = m - n - 1; if 2*A002182(n) is not a highly composite number then a(n) = -1. The zero terms correspond to the terms of A072938, the negative terms correspond to the terms of A073771. The terms were determined by means of A. Flammenkamp's list (cf. Links).

Examples

			a(3) = -1 since 4 is the third highly composite number and 2*4 = 8 is not a highly composite number; a(6) = 1 since 24 is the sixth highly composite number, 2*24 = 48 is the eighth highly composite number and the highly composite number 36 is between them; a(13) = 0 since 360 is the 13th highly composite number, 2*360 = 720 is the 14th highly composite number and there is no highly composite number between them.
		

Crossrefs

A160274 Highly composite numbers A002182(n) with the property that A002182(n+1)/A002182(n) >= A002182(k+1)/A002182(k) for all k>n.

Original entry on oeis.org

1, 2, 6, 12, 60, 360, 2520
Offset: 1

Views

Author

Anonymous, May 07 2009

Keywords

Examples

			2520 is a term of this sequence because 2520 is a highly composite number (A002182(18)), A002182(19)/A002182(18) = 2, and 2 >= A002182(k+1)/A002182(k) for all k>18. (In fact, 2 > A002182(k+1)/A002182(k) for all k>18.)
		

Crossrefs

Previous Showing 11-12 of 12 results.