A095862 -id:A095862 - cp's OEIS frontend

A307980 Numbers k whose number of divisors is the square of the number of decimal digits of k.

1, 10, 14, 15, 21, 22, 26, 27, 33, 34, 35, 38, 39, 46, 51, 55, 57, 58, 62, 65, 69, 74, 77, 82, 85, 86, 87, 91, 93, 94, 95, 100, 196, 225, 256, 441, 484, 676, 1000, 1026, 1032, 1064, 1110, 1122, 1128, 1144, 1155, 1160, 1190, 1218, 1230, 1240, 1242, 1254, 1272, 1288, 1290, 1302, 1326, 1330, 1365, 1408

Offset: 1

Bernard Schott, May 08 2019

The terms with an odd number of digits are squares.
The terms with 2 digits are squarefree semiprimes (cf. A006881) Union {27}. The terms with 3 digits belong to A030627 (numbers with 9 divisors) and the ones with 4 digits belong to A030634 (numbers with 16 divisors).
The number of terms b(n) with n digits begins with: 1, 30, 7, 753, 3, 11409, 2, ... When there are an odd number of digits, the number of terms decreases from b(3) = 7, b(5) = 3, b(7) = 2. Is there a 2q+1 such that b(2q+1) = 0?
The sequence is infinite because 10^k is the term for each k. We have tau(10^k) = tau(2^k)*tau(5^k) = (k + 1)^2 and 10^k has k + 1 digits. - Marius A. Burtea, May 09 2019
a(n) >= 1, for any n, so b(2q+1)>= 1 for any q. - Marius A. Burtea, May 09 2019

			65 is a term with 2 digits and 4 divisors: {1, 5, 13, 65}.
484 is a term with 3 digits and 9 divisors: {1, 2, 4, 11, 22, 44, 121, 242, 484}.

Sean A. Irvine, Java program (github)

Cf. A095862 (number of decimal digits = number of divisors).
Cf. A006881 (squarefree semiprimes).
Cf. A030513 (numbers with 4 divisors), A030627 (numbers with 9 divisors), A030634 (numbers with 16 divisors).
Cf. A011557 (subsequence).

[n:n in [1..1500]|NumberOfDivisors(n) eq (#Intseq(n))^2]; // Marius A. Burtea, May 09 2019

is(n) = numdiv(n) == #digits(n)^2 \\ David A. Corneth, May 08 2019

cp's OEIS Frontend

A307980 Numbers k whose number of divisors is the square of the number of decimal digits of k.

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