cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Previous Showing 11-19 of 19 results.

A186388 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) before g(j) when f(i)=g(j), where f(i)=6i and g(j)=j(j+1)/2 (triangular number). Complement of A186387.

Original entry on oeis.org

1, 2, 4, 5, 7, 9, 11, 14, 16, 19, 22, 25, 28, 31, 35, 38, 42, 46, 50, 55, 59, 64, 69, 74, 79, 84, 90, 95, 101, 107, 113, 120, 126, 133, 140, 147, 154, 161, 169, 176, 184, 192, 200, 209, 217, 226, 235, 244, 253, 262, 272, 281, 291, 301, 311, 322, 332, 343, 354, 365, 376, 387, 399, 410, 422, 434, 446, 459, 471, 484, 497, 510, 523, 536, 550, 563, 577, 591, 605, 620, 634, 649, 664, 679, 694, 709, 725, 740, 756, 772, 788, 805, 821
Offset: 1

Views

Author

Clark Kimberling, Feb 19 2011

Keywords

Examples

			First, write
......6.....12..18....24..30. (6i)
1..3..6..10...15....21..28... (triangular)
Then replace each number by its rank, where ties are settled by ranking 6i before the triangular:
a=(3,6,8,10,12,13,15,17,...)=A186387
b=(1,2,4,5,7,9,11,14,16,...)=A186388.
		

Crossrefs

Programs

A186389 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=6i and g(j)=j(j+1)/2 (triangular number). Complement of A186390.

Original entry on oeis.org

4, 6, 8, 10, 12, 14, 15, 17, 18, 20, 22, 23, 25, 26, 27, 29, 30, 32, 33, 35, 36, 37, 39, 40, 41, 43, 44, 45, 47, 48, 49, 51, 52, 53, 55, 56, 57, 58, 60, 61, 62, 63, 65, 66, 67, 69, 70, 71, 72, 74, 75, 76, 77, 78, 80, 81, 82, 83, 85, 86, 87, 88, 90, 91, 92
Offset: 1

Views

Author

Clark Kimberling, Feb 19 2011

Keywords

Comments

See A186350 for a discussion of adjusted joint rank sequences.

Examples

			First, write
......6.....12..18....24..30. (6i)
1..3..6..10...15....21..28... (triangular)
Then replace each number by its rank, where ties are settled by ranking 6i after the triangular:
a=(4,6,8,10,12,14,15,17,...)=A186389
b=(1,2,3,5,7,9,11,13,16,...)=A186390.
		

Crossrefs

Programs

  • Mathematica
    (* adjusted joint rank sequences a and b, using general formula for ranking 1st degree u*n+v and 2nd degree x*n^2+y*n+z *)
    d=-1/2; u=6; v=0; x=1/2; y=1/2; (* 6i and triangular *)
    h[n_]:=(-y+(4x(u*n+v-d)+y^2)^(1/2))/(2x);
    a[n_]:=n+Floor[h[n]]; (* rank of u*n+v *)
    k[n_]:=(x*n^2+y*n-v+d)/u;
    b[n_]:=n+Floor[k[n]]; (* rank of x*n^2+y*n+d *)
    Table[a[n], {n, 1, 120}]  (* A186389 *)
    Table[b[n], {n, 1, 100}]  (* A186390 *)

A186493 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) before g(j) when f(i)=g(j), where f(i)=5i and g(j)=j-th pentagonal number. Complement of A186494.

Original entry on oeis.org

2, 4, 6, 7, 9, 10, 11, 13, 14, 15, 17, 18, 19, 20, 22, 23, 24, 25, 27, 28, 29, 30, 31, 33, 34, 35, 36, 37, 38, 40, 41, 42, 43, 44, 45, 47, 48, 49, 50, 51, 52, 53, 55, 56, 57, 58, 59, 60, 61, 63, 64, 65, 66, 67, 68, 69, 70, 72, 73, 74, 75, 76, 77, 78, 79, 80, 82, 83, 84, 85, 86, 87, 88, 89, 90, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 126, 127, 128, 129, 130, 131, 132, 133, 134
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Comments

See A186350 for a discussion of adjusted joint rank sequences.

Examples

			First, write
....5..10..15..20..25..30..35..40.. (5i),
1..5......12......22............35..(pentagonal numbers).
Then replace each number by its rank, where ties are settled by ranking 5i before the pentagonal number:
a=(2,4,6,7,9,10,11,13,14,15,17,...)=A186493,
b=(1,3,5,8,12,16,21,26,32,39,46,..)=A186494.
		

Crossrefs

Programs

  • Mathematica
    (* Adjusted joint rank sequences a and b, using general formula for ranking 1st degree u*n+v and 2nd degree x*n^2+y*n+z. *)
    d=1/2; u=5; v=0; x=3/2; y=-1/2;
    h[n_]:=(-y+(4x(u*n+v-d)+y^2)^(1/2))/(2x);
    a[n_]:=n+Floor[h[n]];
    k[n_]:=(x*n^2+y*n-v+d)/u;
    b[n_]:=n+Floor[k[n]];
    Table[a[n],{n,1,120}]  (* A186493 *)
    Table[b[n],{n,1,100}]  (* A186494 *)

A186494 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) before g(j) when f(i)=g(j), where f(i)=5i and g(j)=j-th pentagonal number. Complement of A186493.

Original entry on oeis.org

1, 3, 5, 8, 12, 16, 21, 26, 32, 39, 46, 54, 62, 71, 81, 91, 102, 113, 125, 138, 151, 165, 179, 194, 210, 226, 243, 260, 278, 297, 316, 336, 356, 377, 399, 421, 444, 467, 491, 516, 541, 567, 593, 620, 648, 676, 705, 734, 764, 795, 826, 858, 890, 923, 957, 991, 1026, 1061, 1097, 1134, 1171, 1209, 1247, 1286, 1326, 1366, 1407, 1448, 1490, 1533, 1576, 1620, 1664, 1709, 1755, 1801, 1848, 1895, 1943, 1992, 2041, 2091, 2141
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Examples

			First, write
....5..10..15..20..25..30..35..40.. (5i),
1..5......12......22............35..(pentagonal numbers).
Then replace each number by its rank, where ties are settled by ranking 5i before the pentagonal number:
a=(2,4,6,7,9,10,11,13,14,15,17,...)=A186493,
b=(1,3,5,8,12,16,21,26,32,39,46,..)=A186494.
		

Crossrefs

Programs

A186495 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=5i (A008587) and g(j)=j-th pentagonal number (A000326). Complement of A186496.

Original entry on oeis.org

3, 4, 6, 7, 9, 10, 12, 13, 14, 15, 17, 18, 19, 21, 22, 23, 24, 25, 27, 28, 29, 30, 31, 33, 34, 35, 36, 37, 39, 40, 41, 42, 43, 44, 45, 47, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 59, 60, 61, 63, 64, 65, 66, 67, 68, 69, 70, 72, 73, 74, 75, 76, 77, 78, 79, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 92, 93, 94, 95, 96, 97, 98, 99, 100, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 126, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136, 138, 139, 140
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Examples

			First, write
...5..10..15..20..25..30..35..40... (5i),
1..5......12......22............35..(pentagonal numbers).
Then replace each number by its rank, where ties are settled by ranking 5i after the pentagonal number:
a=(3,4,6,7,9,10,12,13,14,15,17,...)=A186495,
b=(1,2,5,8,11,16,20,26,32,38,46,..)=A186496.
		

Crossrefs

Programs

  • Mathematica
    (* Adjusted joint rank sequences a and b, using general formula for ranking 1st degree u*n+v and 2nd degree x*n^2+y*n+z. *)
    d=-1/2; u=5; v=0; x=3/2; y=-1/2;
    h[n_]:=(-y+(4x(u*n+v-d)+y^2)^(1/2))/(2x);
    a[n_]:=n+Floor[h[n]];
    k[n_]:=(x*n^2+y*n-v+d)/u;
    b[n_]:=n+Floor[k[n]];
    Table[a[n],{n,1,120}]  (* A186495 *)
    Table[b[n],{n,1,100}]  (* A186496 *)

A186496 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) after g(j) when f(i)=g(j), where f(i)=5i and g(j)=j-th pentagonal number. Complement of A186495.

Original entry on oeis.org

1, 2, 5, 8, 11, 16, 20, 26, 32, 38, 46, 53, 62, 71, 80, 91, 101, 113, 125, 137, 151, 164, 179, 194, 209, 226, 242, 260, 278, 296, 316, 335, 356, 377, 398, 421, 443, 467, 491, 515, 541, 566, 593, 620, 647, 676, 704, 734, 764, 794, 826, 857, 890, 923, 956, 991, 1025, 1061, 1097, 1133, 1171, 1208, 1247, 1286, 1325, 1366, 1406, 1448, 1490, 1532, 1576, 1619, 1664, 1709, 1754, 1801, 1847, 1895, 1943, 1991, 2041
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Examples

			First, write
...5..10..15..20..25..30..35..40... (5i),
1..5......12......22............35..(pentagonal numbers).
Then replace each number by its rank, where ties are settled by ranking 5i after the pentagonal number:
a=(3,4,6,7,9,10,12,13,14,15,17,...)=A186495,
b=(1,2,5,8,11,16,20,26,32,38,46,..)=A186496.
		

Crossrefs

Programs

A186354 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) before g(j) when f(i)=g(j), where f(i)=3i and g(j)=j(j+1)/2 (triangular number). Complement of A186355.

Original entry on oeis.org

2, 4, 6, 8, 9, 11, 12, 14, 15, 17, 18, 19, 21, 22, 23, 25, 26, 27, 29, 30, 31, 32, 34, 35, 36, 37, 39, 40, 41, 42, 44, 45, 46, 47, 48, 50, 51, 52, 53, 54, 56, 57, 58, 59, 60, 62, 63, 64, 65, 66, 67, 69, 70, 71, 72, 73, 74, 76, 77, 78, 79, 80, 81, 83, 84, 85, 86, 87, 88, 89, 91, 92, 93, 94, 95, 96, 97, 99, 100, 101, 102, 103, 104, 105, 107, 108, 109, 110, 111, 112, 113, 114, 116, 117, 118, 119, 120, 121, 122, 123, 125, 126, 127, 128, 129, 130, 131, 132, 134, 135
Offset: 1

Views

Author

Clark Kimberling, Feb 18 2011

Keywords

Comments

See A186350.

Examples

			First, write
...3..6..9....12..15..18..21..24.. (3*i)
1..3..6....10.....15......21.... (triangular)
Then replace each number by its rank, where ties are settled by ranking 3i before the triangular:
a=(2,4,6,8,9,11,12,14,15,17,....)=A186354
b=(1,3,5,7,10,13,16,20,24,28,...)=A186355.
		

Crossrefs

Programs

  • Mathematica
    (* adjusted joint rank sequences a and b, using general formula for ranking 1st degree u*n+v and 2nd degree x*n^2+y*n+z *)
    d=1/2; u=3; v=0; x=1/2; y=1/2; (* odds and triangular *)
    h[n_]:=(-y+(4x(u*n+v-d)+y^2)^(1/2))/(2x);
    a[n_]:=n+Floor[h[n]]; (* rank of u*n+v *)
    k[n_]:=(x*n^2+y*n-v+d)/u;
    b[n_]:=n+Floor[k[n]]; (* rank of x*n^2+y*n+d *)
    Table[a[n],{n,1,120}]  (* A186354 *)
    Table[b[n],{n,1,100}]  (* A186355 *)

A186497 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) before g(j) when f(i)=g(j), where f(i)=3i-2 and g(j)=j-th triangular number. Complement of A186498.

Original entry on oeis.org

1, 4, 6, 7, 9, 11, 12, 14, 15, 16, 18, 19, 21, 22, 23, 25, 26, 27, 28, 30, 31, 32, 34, 35, 36, 37, 39, 40, 41, 42, 43, 45, 46, 47, 48, 50, 51, 52, 53, 54, 56, 57, 58, 59, 60, 61, 63, 64, 65, 66, 67, 69, 70, 71, 72, 73, 74, 76, 77, 78, 79, 80, 81, 82, 84, 85, 86, 87, 88, 89, 91, 92, 93, 94, 95, 96, 97, 99, 100, 101, 102, 103, 104, 105, 106, 108, 109, 110, 111, 112, 113, 114, 116, 117, 118, 119, 120, 121, 122, 123, 125, 126, 127, 128, 129, 130, 131, 132, 133, 135, 136, 137, 138, 139, 140, 141, 142, 144, 145, 146
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Comments

See A186350 for a discussion of adjusted joint rank sequences.

Examples

			First, write
1..4..7.10..13..16..19..22..25..28..31. (3i-2),
1.3..6..10....15.......21.......28.....(j(j+1)/2).
Then replace each number by its rank, where ties are settled by ranking 3i-2 before j(j+1)/2:
a=(1,4,6,7,9,11,12,14,15,16,18,...)=A186497,
b=(2,3,5,8,10,13,17,20,24,29,33,..)=A186498.
		

Crossrefs

Programs

  • Mathematica
    (* Adjusted joint rank sequences a and b, using general formula for ranking 1st degree u*n+v and 2nd degree x*n^2+y*n+z. *)
    d=1/2; u=3; v=-2; x=1/2; y=1/2;
    h[n_]:=(-y+(4x(u*n+v-d)+y^2)^(1/2))/(2x);
    a[n_]:=n+Floor[h[n]];
    k[n_]:=(x*n^2+y*n-v+d)/u;
    b[n_]:=n+Floor[k[n]];
    Table[a[n],{n,1,120}]  (* A186497 *)
    Table[b[n],{n,1,100}]  (* A186498 *)

A186498 Adjusted joint rank sequence of (f(i)) and (g(j)) with f(i) before g(j) when f(i)=g(j), where f(i)=3i-2 and g(j)=j-th triangular number. Complement of A186497.

Original entry on oeis.org

2, 3, 5, 8, 10, 13, 17, 20, 24, 29, 33, 38, 44, 49, 55, 62, 68, 75, 83, 90, 98, 107, 115, 124, 134, 143, 153, 164, 174, 185, 197, 208, 220, 233, 245, 258, 272, 285, 299, 314, 328, 343, 359, 374, 390, 407, 423, 440, 458, 475, 493, 512, 530, 549, 569, 588, 608, 629, 649, 670, 692, 713, 735, 758, 780, 803, 827, 850, 874, 899, 923, 948, 974, 999, 1025, 1052, 1078, 1105, 1133, 1160, 1188, 1217, 1245, 1274, 1304
Offset: 1

Views

Author

Clark Kimberling, Feb 22 2011

Keywords

Examples

			First, write
1..4..7.10..13..16..19..22..25..28..31. (3i-2),
1.3..6..10....15.......21.......28.....(j(j+1)/2).
Then replace each number by its rank, where ties are settled by ranking 3i-2 before j(j+1)/2:
a=(1,4,6,7,9,11,12,14,15,16,18,...)=A186497,
b=(2,3,5,8,10,13,17,20,24,29,33,..)=A186498.
		

Crossrefs

Programs

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