cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A090338 Number of ways of arranging n straight lines in general position in the (affine) plane.

Original entry on oeis.org

1, 1, 1, 1, 1, 6, 43, 922, 38609, 3111341
Offset: 0

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Author

Jon Wild and Laurence Reeves, Jan 27 2004

Keywords

Comments

This is in the affine plane, rather than the projective plane, so two lines are either parallel or meet in one point.
Here we only consider arrangements of n lines in "general position", with every two lines meeting in one point and every intersection point lying on exactly two lines. See A241600 for the general case.
Two arrangements are considered the same if the lines in each arrangement can be numbered from 1 to n in such a way that, on each line, the order of crossings with the other lines is the same in the two arrangements. In particular, turning over the whole arrangement is allowed. (This does not imply that one arrangement can be continuously changed to the other (possibly after turning over) while keeping all lines straight, without changing the multiplicity of intersection points, and without a line passing through an intersection point, see the papers by Suvorov, Jaggi et al., Richter-Gebert, and Tsukamoto.)
Old name was "Number of full n-flups". The full n-flups are the topologically distinct planar configurations of n straight lines such that each line crosses each other line at exactly one intersection point and no two intersection points coincide.
Also, the number of distinct ways to divide a pancake with n straight cuts that result in the maximal number of pieces (see A000124, A000125).

Examples

			See illustration of a(5), the full pentaflups. Of the six, the last shown does not have reflectional symmetry, but we do not count its mirror image as distinct. All six are drawn with lines at equally-spaced angles; it is usually (but not always) possible to achieve this (41 out of 43 of the full 6-flups, for example, have equi-angled drawings)
		

Crossrefs

Cf. A000124, A000125, A090339 (when the lines need not be straight), A241600, A250001.

Extensions

Edited by Max Alekseyev, May 15 2014
Further edits by N. J. A. Sloane, May 16 2014
a(9) from Christ added, and comments corrected by Günter Rote, Apr 14 2025

A241600 Number of ways of arranging n lines in the (affine) plane.

Original entry on oeis.org

1, 1, 2, 4, 9, 47, 791, 37830
Offset: 0

Views

Author

Max Alekseyev and N. J. A. Sloane, May 15 2014

Keywords

Comments

This is in the affine plane, rather than the projective plane, so lines are either parallel or meet in one point.
Two arrangements are considered the same if one can be continuously changed to the other while keeping all lines straight, without changing the multiplicity of intersection points, and without a line passing through an intersection point. Turning over is also allowed.
a(n) might be called the size of the moduli space of n lines in the affine plane.
The subsequence giving the number of arrangements G_n of n lines in "general position" (with every two lines meeting in one point and every intersection point lying on exactly two lines) is given by A090338.
The moduli space of n points in the affine plane has been studied by several people (see for example Haiman and Miller, 2004; Martin, 2003). There is no direct connection with this problem, but these references are included for background information. - N. J. A. Sloane, Sep 13 2014
Lukas Finschi points out (email, Sep 19 2014) that a(n) = A063859(n)+1 for n <= 7 (but not for larger n). - N. J. A. Sloane, Sep 20 2014

Examples

			Let P_n = n parallel lines, S_n = star of n lines through a point, G_n = n lines in general position, L = P_1 = S_1 = G_1 = a single line.
a(1) = 1: L.
a(2) = 2: P_2, S_2.
a(3) = 4: P_3, P_2 L, S_3, G_3.
See link for illustrations of first 5 terms.
		

References

  • B. Grünbaum, Arrangements and Spreads. American Mathematical Society, Providence, RI, 1972, p. 4.

Crossrefs

Cf. A090338 (lines in general position), A090339 (curved lines in general position), A250001 (circles).

Formula

a(n) >= A000041(n). - Pablo Hueso Merino, May 10 2021

Extensions

a(6) and a(7) from Lukas Finschi, Sep 19 2014

A249752 Triangle read by rows: T(n,k) = number of arrangements of n circles in the affine plane having k outer circles.

Original entry on oeis.org

1, 1, 2, 3, 5, 6, 14, 52, 60, 47
Offset: 1

Views

Author

Omar E. Pol, Dec 14 2014

Keywords

Comments

Consider the arrangements of n circles described in A250001.
T(n,k) is the number of arrangements of n circles in the affine plane whose perimeters are formed with parts from k circles. - Omar E. Pol, Aug 09 2015
From Omar E. Pol, Jul 06 2016: (Start)
Observation 1: column 1 gives A250001, at least if 1<=n<=4.
Observation 2: sum of n-th row = T(n+1,1), at least if 1<=n<=3. (End)

Examples

			Triangle begins:
1;
1,   2;
3,   5,  6;
14, 52, 60, 47;
...
		

Crossrefs

Sum of n-th row = A250001(n).
Leading diagonal gives A274702.

Extensions

Corrected a(5)-a(6) and added a(7)-a(10) from Omar E. Pol, Oct 13 2015

A252158 Triangle read by rows, 1 <= k <= n, T(n,k) = number of arrangements of n circles in the affine plane having k solid regions in which the union of solid circles is connected.

Original entry on oeis.org

1, 2, 1, 11, 2, 1, 155, 15, 2, 1
Offset: 1

Views

Author

Omar E. Pol, Dec 14 2014

Keywords

Comments

Consider the rules for the arrangements of n circles described in A250001.
Right border gives A000012. - Omar E. Pol, Aug 09 2015
From Omar E. Pol, May 21 2017: (Start)
Note that T(4,1) = 155 does not include the arrangement of four circles in which there is a central circle that is surrounded by the union of three circles, because in that arrangement there are two solid regions, not one. The smallest solid region is formed by the central solid circle. The largest solid region is formed by the union of three solid circles.
T(4,2) = 15 includes the arrangement mentioned above.
1 together with the first column gives A287149.
For another version see A285996. (End) (Comment clarified on Jun 15 2017.)

Examples

			Triangle begins:
1;
2,   1;
11,  2,   1;
155, 15,  2,  1;
		

Crossrefs

Row sums give A250001, n >= 1.
Cf. A249752, A285996 (another version), A287149.

Extensions

Clarified definition and a(7)-a(10) added by Omar E. Pol, May 21 2017
Clarified definition and comment by Omar E. Pol, Jun 15 2017

A383083 The number of distinct straightedge-and-compass constructions that can be made with no lines and n circles.

Original entry on oeis.org

1, 2, 1, 4, 44, 1084, 91192
Offset: 0

Views

Author

Peter Kagey, Apr 16 2025

Keywords

Comments

A straightedge-and-compass construction starts with 2 points marked on the plane, traditionally (0,0) and (1,0). In the constructions counted by this sequence, only the compass is used. Circles can be drawn at any marked point through any other marked point, and new points are marked where circles intersect.

Crossrefs

A274776 Irregular triangle read by rows: T(n,k) = number of arrangements of n circles in the affine plane forming k regions, including the regions that do not belong to the circles.

Original entry on oeis.org

1, 0, 2, 1, 0, 0, 4, 4, 2, 0, 4, 0, 0, 0
Offset: 1

Views

Author

Omar E. Pol, Jul 06 2016

Keywords

Comments

Consider the arrangements of n circles described in A250001.
Note that the sum of the 4th row must be equal to A250001(4) = 173.

Examples

			Triangle begins:
1;
0, 2, 1;
0, 0, 4, 4, 2, 0, 4;
0, 0, 0, ...
...
For n = 3 and k = 5 there are 2 arrangements of 3 circles in the affine plane forming 5 regions, including the regions that do not belong to the circles, so T(3,5) = 2.
For n = 3 and k = 6 there are no arrangements of 3 circles in the affine plane forming 6 regions, including the regions that do not belong to the circles, so T(3,6) = 0.
Of course, there is a right triangle of all zeros starting from the second row.
		

Crossrefs

Sum of n-th row = A250001(n).
First differs from A274777 at a(10).

Formula

T(n,k) = A274818(n,k)/k.

A274777 Irregular triangle read by rows: T(n,k) = number of arrangements of n circles in the affine plane forming k regions, excluding the regions that do not belong to the circles.

Original entry on oeis.org

1, 0, 2, 1, 0, 0, 4, 4, 2, 1, 3, 0, 0, 0
Offset: 1

Views

Author

Omar E. Pol, Jul 06 2016

Keywords

Comments

In other words: not counting the regions between circles.
Consider the arrangements of n circles described in A250001.
Note that the sum of the 4th row must be equal to A250001(4) = 173.

Examples

			Triangle begins:
1;
0, 2, 1;
0, 0, 4, 4, 2, 1, 3;
0, 0, 0, ...
...
For n = 3 and k = 5 there are 2 arrangements of 3 circles in the affine plane forming 5 regions, excluding the regions that do not belong to the circles, so T(3,5) = 2.
For n = 3 and k = 6 there is only one arrangement of 3 circles in the affine plane forming 6 regions, excluding the regions that do not belong to the circles, so T(3,6) = 1.
Of course, there is a right triangle of all zeros starting from the second row.
		

Crossrefs

Sum of n-th row = A250001(n).
First differs from A274776 at a(10).

Formula

T(n,k) = A274819(n,k)/k.

A288559 Number of arrangements of n pseudo-circles in the affine plane.

Original entry on oeis.org

1, 1, 3, 14, 173, 16977, 17552169
Offset: 0

Views

Author

N. J. A. Sloane, Jun 13 2017, based on information supplied by Jon Wild on Aug 31 2016

Keywords

Comments

These counts have been reduced for mirror symmetry.
See A250001, the main entry for this problem, for further information.
This sequence is also an upper bound for A250001. - Andrii Shportko, Jun 03 2025

Crossrefs

Extensions

After consulting with Jon Wild, a(6) added by Andrii Shportko, Jun 03 2025

A274818 Triangle read by rows: T(n,k) = total number of regions in all arrangements of n circles in the affine plane forming k regions, including the regions that do not belong to the circles.

Original entry on oeis.org

1, 0, 4, 3, 0, 0, 12, 16, 10, 0, 28, 0, 0, 0
Offset: 1

Views

Author

Omar E. Pol, Jul 07 2016

Keywords

Comments

Consider the arrangements of n circles described in A250001.

Examples

			Triangle begins:
1;
0, 4,  3;
0, 0, 12, 16, 10, 0, 28;
0, 0,  0, ...
...
For n = 3 and k = 5 there are 2 arrangements of 3 circles in the affine plane forming 5 regions, including the regions that do not belong to the circles, so T(3,5) = 2*5 = 10.
For n = 3 and k = 6 there are no arrangements of 3 circles in the affine plane forming 6 regions, including the regions that do not belong to the circles, so T(3,6) = 0*5 = 0.
Of course, there is a right triangle of all zeros starting from the second row.
		

Crossrefs

Row sums give A274822.
First differs from A274819 at a(10).

Formula

T(n,k) = k*A274776(n,k).

A274819 Triangle read by rows: T(n,k) = total number of regions in all arrangements of n circles in the affine plane forming k regions, excluding the regions that do not belong to the circles.

Original entry on oeis.org

1, 0, 4, 3, 0, 0, 12, 16, 10, 6, 21, 0, 0, 0
Offset: 1

Views

Author

Omar E. Pol, Jul 07 2016

Keywords

Comments

In other words: not counting the regions between circles.
Consider the arrangements of n circles described in A250001.

Examples

			Triangle begins:
1;
0, 4,  3;
0, 0, 12, 16, 10, 6, 21;
0, 0,  0, ...
...
For n = 3 and k = 5 there are 2 arrangements of 3 circles in the affine plane forming 5 regions, excluding the regions that do not belong to the circles, so T(3,5) = 2*5 = 10.
For n = 3 and k = 6 there is only one arrangement of 3 circles in the affine plane forming 6 regions, excluding the regions that do not belong to the circles, so T(3,6) = 1*6 = 6.
Of course, there is a right triangle of all zeros starting from the second row.
		

Crossrefs

Row sums give A274823(n).
First differs from A274818 at a(10).

Formula

T(n,k) = k*A274777(n,k).
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