cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Previous Showing 21-30 of 43 results. Next

A296480 Decimal expansion of limiting power-ratio for A295951; see Comments.

Original entry on oeis.org

6, 7, 4, 9, 9, 1, 8, 6, 6, 2, 0, 4, 9, 9, 8, 5, 4, 2, 4, 8, 2, 8, 6, 9, 9, 4, 6, 5, 3, 9, 4, 5, 6, 5, 2, 9, 3, 9, 8, 7, 5, 7, 7, 8, 3, 5, 3, 9, 8, 6, 1, 5, 6, 8, 6, 8, 6, 8, 3, 7, 0, 5, 3, 8, 9, 4, 4, 1, 6, 6, 7, 1, 9, 7, 8, 9, 3, 8, 2, 8, 9, 1, 7, 9, 7, 4
Offset: 1

Views

Author

Clark Kimberling, Jan 05 2018

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The limiting power-ratio for A is the limit as n->oo of a(n)/g^n, assuming that this limit exists. For A = A295951, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			limiting power-ratio = 6.749918662049985424828699465394565293987...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 2; a[1] = 3; b[0] = 1; b[1 ] = 4; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 13, k = a[j] - j - 1;
     While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295951 *)
    z = 2000; g = GoldenRatio; h = Table[N[a[n]/g^n, z], {n, 0, z}];
    StringJoin[StringTake[ToString[h[[z]]], 41], "..."]
    Take[RealDigits[Last[h], 10][[1]], 120]   (* A296480 *)

A296481 Decimal expansion of ratio-sum for A295952; see Comments.

Original entry on oeis.org

4, 8, 4, 5, 8, 5, 3, 6, 8, 3, 5, 1, 4, 3, 6, 2, 0, 7, 1, 3, 5, 0, 0, 2, 0, 5, 6, 7, 3, 7, 2, 5, 0, 1, 7, 8, 9, 0, 3, 4, 8, 4, 3, 5, 6, 2, 3, 5, 7, 9, 0, 5, 1, 6, 3, 2, 0, 5, 9, 9, 3, 0, 5, 7, 2, 8, 9, 5, 5, 2, 9, 0, 7, 4, 0, 0, 5, 7, 1, 0, 7, 9, 6, 9, 5, 0
Offset: 1

Views

Author

Clark Kimberling, Jan 05 2018

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The ratio-sum for A is |a(1)/a(0) - g| + |a(2)/a(1) - g| + ..., assuming that this series converges. For A = A295952, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			ratio-sum = 4.845853683514362071350020567372501789034...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 5; b[0] = 2; b[1 ] = 3; b[2] = 4;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295952 *)
    g = GoldenRatio; s = N[Sum[- g + a[n]/a[n - 1], {n, 1, 1000}], 200]
    Take[RealDigits[s, 10][[1]], 100]  (* A296481 *)

A296482 Decimal expansion of limiting power-ratio for A295952; see Comments.

Original entry on oeis.org

7, 0, 9, 0, 7, 0, 0, 6, 8, 7, 3, 5, 5, 1, 4, 2, 8, 8, 1, 1, 6, 7, 7, 4, 7, 5, 2, 6, 5, 0, 3, 3, 7, 1, 2, 1, 5, 9, 2, 1, 8, 4, 1, 1, 4, 6, 6, 7, 4, 7, 0, 1, 0, 3, 6, 6, 9, 0, 6, 0, 7, 5, 9, 3, 3, 6, 3, 2, 5, 5, 4, 8, 7, 9, 1, 6, 3, 6, 2, 1, 8, 8, 7, 8, 3, 5
Offset: 1

Views

Author

Clark Kimberling, Jan 06 2018

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The limiting power-ratio for A is the limit as n->oo of a(n)/g^n, assuming that this limit exists. For A = A295952, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			limiting power-ratio = 7.090700687355142881167747526503371215921...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 5; b[0] = 2; b[1 ] = 3; b[2] = 4;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n];
    j = 1; While[j < 13, k = a[j] - j - 1;
     While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295952 *)
    z = 2000; g = GoldenRatio; h = Table[N[a[n]/g^n, z], {n, 0, z}];
    StringJoin[StringTake[ToString[h[[z]]], 41], "..."]
    Take[RealDigits[Last[h], 10][[1]], 120]   (* A296482 *)

A296483 Decimal expansion of ratio-sum for A295953; see Comments.

Original entry on oeis.org

4, 1, 9, 4, 6, 7, 8, 6, 7, 9, 0, 5, 6, 3, 7, 1, 7, 5, 8, 9, 9, 1, 8, 4, 0, 8, 1, 8, 1, 2, 3, 9, 5, 4, 4, 2, 0, 9, 6, 4, 7, 0, 2, 4, 0, 5, 8, 5, 4, 7, 6, 3, 3, 6, 2, 6, 1, 4, 0, 4, 4, 6, 3, 6, 5, 8, 9, 0, 0, 9, 3, 9, 1, 9, 0, 4, 2, 3, 2, 8, 2, 0, 5, 9, 0, 0
Offset: 1

Views

Author

Clark Kimberling, Jan 06 2018

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The ratio-sum for A is |a(1)/a(0) - g| + |a(2)/a(1) - g| + ..., assuming that this series converges. For A = A295953, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			ratio-sum = 4.194678679056371758991840818123954420964...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 3; b[0] = 2; b[1 ] = 4; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n] + 1;
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295953 *)
    g = GoldenRatio; s = N[Sum[- g + a[n]/a[n - 1], {n, 1, 1000}], 200]
    Take[RealDigits[s, 10][[1]], 100]  (* A296483 *)

A296485 Decimal expansion of ratio-sum for A295960; see Comments.

Original entry on oeis.org

3, 5, 5, 6, 9, 5, 8, 4, 3, 6, 6, 6, 0, 9, 0, 3, 9, 9, 5, 0, 9, 7, 5, 4, 8, 4, 9, 4, 4, 5, 1, 0, 9, 7, 9, 3, 8, 7, 2, 8, 1, 4, 4, 3, 9, 8, 3, 5, 4, 0, 8, 0, 9, 1, 7, 6, 4, 5, 5, 7, 3, 6, 9, 2, 4, 6, 5, 5, 1, 9, 7, 7, 2, 6, 3, 7, 5, 6, 7, 1, 7, 9, 0, 9, 3, 9
Offset: 1

Views

Author

Clark Kimberling, Apr 12 2018

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The ratio-sum for A is |a(1)/a(0) - g| + |a(2)/a(1) - g| + ..., assuming that this series converges. For A = A295960, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			ratio-sum = 3.556958436660903995097548494451097938728...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 3; b[0] = 2; b[1 ] = 4; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n] - 1;
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295960 *)
    g = GoldenRatio; s = N[Sum[- g + a[n]/a[n - 1], {n, 1, 1000}], 200]
    Take[RealDigits[s, 10][[1]], 100]  (* A296485 *)

A296486 Decimal expansion of limiting power-ratio for A295960; see Comments.

Original entry on oeis.org

5, 8, 5, 9, 9, 9, 6, 6, 2, 9, 8, 4, 4, 6, 4, 4, 0, 3, 1, 2, 8, 6, 0, 3, 5, 7, 7, 5, 8, 6, 0, 5, 4, 2, 6, 0, 8, 8, 1, 6, 1, 8, 8, 8, 4, 6, 3, 9, 7, 2, 6, 3, 6, 1, 0, 1, 9, 6, 8, 1, 0, 0, 1, 8, 7, 9, 9, 3, 6, 3, 9, 4, 8, 0, 6, 9, 6, 5, 7, 1, 0, 4, 5, 7, 9, 5
Offset: 1

Views

Author

Clark Kimberling, Apr 13 2018

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The limiting power-ratio for A is the limit as n->oo of a(n)/g^n, assuming that this limit exists. For A = A295960, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			limiting power-ratio = 5.859996629844644031286035775860542608816...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 3; b[0] = 2; b[1 ] = 4; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n] - 1;
    j = 1; While[j < 13, k = a[j] - j - 1;
     While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A295960 *)
    z = 2000; g = GoldenRatio; h = Table[N[a[n]/g^n, z], {n, 0, z}];
    StringJoin[StringTake[ToString[h[[z]]], 41], "..."]
    Take[RealDigits[Last[h], 10][[1]], 120]   (* A296486 *)

A296487 Decimal expansion of ratio-sum for A293076; see Comments.

Original entry on oeis.org

3, 0, 9, 2, 2, 6, 2, 2, 8, 5, 7, 7, 3, 1, 0, 6, 3, 3, 0, 1, 8, 3, 5, 3, 4, 6, 5, 5, 2, 0, 2, 7, 1, 6, 1, 6, 2, 4, 2, 5, 9, 4, 5, 8, 5, 3, 6, 9, 4, 2, 4, 6, 2, 4, 5, 5, 0, 6, 7, 2, 9, 0, 8, 0, 6, 9, 5, 8, 3, 5, 9, 6, 3, 1, 8, 2, 6, 8, 5, 5, 6, 2, 4, 7, 7, 3
Offset: 1

Views

Author

Clark Kimberling, Dec 19 2017

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The ratio-sum for A is |a(1)/a(0) - g| + |a(2)/a(1) - g| + ..., assuming that this series converges. For A = A293076, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			ratio-sum = 3.092262285773106330183534655202716162425...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 3; b[0] = 2; b[1 ] = 4;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n - 2];
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A293076 *)
    g = GoldenRatio; s = N[Sum[- g + a[n]/a[n - 1], {n, 1, 1000}], 200]
    Take[RealDigits[s, 10][[1]], 100]  (* A296487 *)

A296488 Decimal expansion of limiting power-ratio for A293076; see Comments.

Original entry on oeis.org

4, 8, 6, 3, 6, 9, 8, 8, 6, 8, 1, 5, 6, 0, 7, 9, 1, 9, 5, 8, 5, 9, 8, 8, 8, 7, 5, 2, 1, 4, 9, 6, 5, 7, 1, 9, 8, 7, 1, 7, 4, 9, 0, 9, 2, 2, 2, 5, 6, 9, 4, 8, 8, 2, 3, 8, 9, 7, 6, 2, 2, 3, 2, 9, 1, 6, 7, 9, 6, 4, 4, 5, 0, 1, 6, 1, 7, 1, 3, 3, 9, 0, 8, 6, 3, 9
Offset: 1

Views

Author

Clark Kimberling, Dec 19 2017

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The limiting power-ratio for A is the limit as n->oo of a(n)/g^n, assuming that this limit exists. For A = A293076, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			limiting power-ratio = 4.863698868156079195859888752149657198717...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 3; b[0] = 2; b[1 ] = 4; b[2] = 5;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n - 2];
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A293076 *)
    z = 2000; g = GoldenRatio; h = Table[N[a[n]/g^n, z], {n, 0, z}];
    StringJoin[StringTake[ToString[h[[z]]], 41], "..."]
    Take[RealDigits[Last[h], 10][[1]], 120]   (* A296488 *)

A296489 Decimal expansion of ratio-sum for A293358; see Comments.

Original entry on oeis.org

3, 5, 3, 5, 9, 1, 7, 3, 9, 3, 5, 1, 5, 2, 5, 9, 3, 5, 0, 7, 1, 6, 8, 0, 2, 2, 3, 2, 2, 4, 8, 5, 5, 0, 6, 7, 3, 3, 5, 5, 7, 5, 3, 4, 6, 2, 2, 7, 4, 4, 6, 8, 4, 2, 8, 0, 2, 2, 1, 0, 8, 9, 2, 8, 7, 4, 5, 0, 0, 5, 1, 2, 4, 2, 3, 1, 0, 0, 6, 9, 4, 5, 5, 7, 8, 9
Offset: 1

Views

Author

Clark Kimberling, Dec 19 2017

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The ratio-sum for A is |a(1)/a(0) - g| + |a(2)/a(1) - g| + ..., assuming that this series converges. For A = A293358, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			ratio-sum = 3.535917393515259350716802232248550673355...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 3; b[0] = 2; b[1 ] = 4;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n - 1];
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A293358 *)
    g = GoldenRatio; s = N[Sum[- g + a[n]/a[n - 1], {n, 1, 1000}], 200]
    Take[RealDigits[s, 10][[1]], 100]  (* A296489 *)

A296490 Decimal expansion of limiting power-ratio for A293358; see Comments.

Original entry on oeis.org

5, 7, 9, 2, 4, 9, 7, 4, 8, 4, 5, 2, 1, 0, 7, 5, 8, 9, 2, 7, 4, 7, 7, 3, 8, 0, 7, 5, 8, 8, 2, 8, 6, 7, 0, 1, 6, 8, 2, 2, 1, 4, 0, 8, 1, 7, 6, 5, 1, 7, 1, 8, 4, 0, 3, 6, 8, 7, 8, 9, 0, 1, 1, 6, 2, 1, 6, 4, 9, 0, 0, 2, 9, 3, 3, 6, 0, 6, 8, 1, 1, 4, 4, 6, 9, 4
Offset: 1

Views

Author

Clark Kimberling, Dec 19 2017

Keywords

Comments

Suppose that A = (a(n)), for n >= 0, is a sequence, and g is a real number such that a(n)/a(n-1) -> g. The limiting power-ratio for A is the limit as n->oo of a(n)/g^n, assuming that this limit exists. For A = A293358, we have g = (1 + sqrt(5))/2, the golden ratio (A001622). See the guide at A296469 for related sequences.

Examples

			limiting power-ratio = 5.792497484521075892747738075882867016822...
		

Crossrefs

Programs

  • Mathematica
    a[0] = 1; a[1] = 3; b[0] = 2; b[1 ] = 4;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n - 1];
    j = 1; While[j < 13, k = a[j] - j - 1;
    While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++];
    Table[a[n], {n, 0, k}]; (* A293358 *)
    z = 2000; g = GoldenRatio; h = Table[N[a[n]/g^n, z], {n, 0, z}];
    StringJoin[StringTake[ToString[h[[z]]], 41], "..."]
    Take[RealDigits[Last[h], 10][[1]], 120]   (* A296490 *)
Previous Showing 21-30 of 43 results. Next