A290867 Irregular triangle read by rows: the number of points that are the intersections of k semicircles in the configuration A290447(n).
0, 0, 0, 0, 1, 0, 5, 0, 15, 0, 35, 0, 70, 0, 123, 1, 0, 195, 5, 0, 285, 15, 0, 420, 25, 0, 586, 39, 2, 0, 818, 53, 4, 0, 1110, 73, 6, 0, 1451, 103, 10, 0, 1846, 142, 18, 0, 2361, 181, 26, 0, 2956, 234, 33, 2, 0, 3704, 287, 40, 4, 0, 4567, 348, 49, 8
Offset: 1
Examples
Triangle begins: 0; 0; 0; 0, 1; 0, 5; 0, 15; 0, 35; 0, 70; 0, 123, 1; 0, 195, 5; 0, 285, 15; 0, 420, 25; 0, 586, 39, 2;
Links
- David Applegate, Table of n, a(n) for n = 1..800
- David Applegate, Triangular table T(n,k) for n = 1..100
- N. J. A. Sloane, Three (No, 8) Lovely Problems from the OEIS, Experimental Mathematics Seminar, Rutgers University, Oct 05 2017, Part I, Part 2, Slides. (Mentions this sequence)
- N. J. A. Sloane (in collaboration with Scott R. Shannon), Art and Sequences, Slides of guest lecture in Math 640, Rutgers Univ., Feb 8, 2020. Mentions this sequence.
Formula
Sum_{k} T(n,k) * binomial(k,2) = binomial(n,4), because there are binomial(n,4) total pairs of semicircles, and an intersection of k consists of binomial(k,2) of those pairs.
A290865(n) = binomial(n,2) + Sum_{k} T(n,k) * (k-1).
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