A247155 a(n) = 31*n^2 + 1.
1, 32, 125, 280, 497, 776, 1117, 1520, 1985, 2512, 3101, 3752, 4465, 5240, 6077, 6976, 7937, 8960, 10045, 11192, 12401, 13672, 15005, 16400, 17857, 19376, 20957, 22600, 24305, 26072, 27901, 29792, 31745, 33760, 35837, 37976, 40177, 42440, 44765, 47152, 49601
Offset: 0
Links
- Index entries for linear recurrences with constant coefficients, signature (3,-3,1).
Crossrefs
Cf. A010020.
Programs
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Mathematica
31*Range[100]^2+1 (* or *) LinearRecurrence[{3,-3,1},{32,125,280},100] (* Harvey P. Dale, Apr 28 2016 *) -
PARI
a(n)=31*n^2+1 \\ Charles R Greathouse IV, Jun 17 2017
Formula
a(0)=1, a(1)=32, a(2)=125, a(3)=280, a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3). - Harvey P. Dale, Apr 28 2016
From Elmo R. Oliveira, Nov 29 2024: (Start)
G.f.: (32*x^2+29*x+1)/(1-x)^3.
E.g.f.: exp(x)*(1 + 31*x + 31*x^2).
a(n) = A010020(n) - 1 for n>=1. (End)